We want to find the probability of getting a red ball in our first draw, given that in the second draw we got a white ball.
We will get P = 0.345
We know that the bowl has:
- 5 white balls
- 10 red balls
- 15 blue balls.
For a total of 30 balls.
We draw a ball and we store it.
Then we draw another ball and we see that it is a white ball.
We want to get the probability that the first ball was red.
The only thing we know, is that one of the white balls can be taken out of the sample space, because we can only draw it second if we did not draw it on the first attempt.
Then we can think that we have:
- 4 white balls.
- 10 red balls
- 15 blue balls.
For a total of 29 balls.
Then the probability of getting a red one is just the quotient between the number of red balls and the total number of balls, we will get:
P = 10/29 = 0.345
If you want to learn more, you can read:
brainly.com/question/11234923
Answer:
C.
Step-by-step explanation:
Answer: 4,840,000 square meters
Step-by-step explanation:
Each square has an area of (400m)^2 or 160,000 m^2 each square.
There are 390 squares, so:
(30 squares)*(160,000 m^2/square) = 4,800,000 m^2
4,840,000 square meters comes closest
Taking
gives
, so that the integral becomes
When
, we have
and from here we can substitute
to proceed from here.
Quick note: When we set
, we are implicitly enforcing
just so that the substitution can be undone later via
. But note that over this domain, we automatically guarantee that
, so the absolute value bars can be dropped immediately.
The answer is 48 because you multiple four and 12 because they used twice the amount
