14: 1 × 14
2 × 7
56: 1 × 56
2 × 28
4 × 14
7 × 8
63: 1 × 63
3 × 21
7 × 9
GCF(14, 56, 63) = 7
Answer:
Step-by-step explanation:
There are <u>6</u><u> different shapes</u>
You want the outcome to be a Nonagon
You put the outcome as a ratio 1/6
1/6=0.1666667
0.1666667*100=16.6667%
<u>Chance of pulling out a </u><u>nonagon</u>
Answer:
53.08 ft
Step-by-step explanation:
The pressure at the bottom of the tank, P = ρgh where ρ = density of water = 1000 kg/m³, g = acceleration due to gravity = 9.8 m/s² and h = depth of water in tank.
Since the pressure at the bottom of the tank, P = ρgh, making h subject of the formula, we have
h = P/ρg
Since P = 23 psig = 23 × 1 psig = 23 × 6894.76 Pa = 158579.48 Pa
Substituting the values of the other variables into h, we have
h = P/ρg
h = 158579.48 Pa/(1000 kg/m³ × 9.8 m/s²)
h = 158579.48 Pa/(9800 kg/m²s²)
h = 16.18 m
h = 16.18 × 1 m
h = 16.18 × 3.28 ft
h = 53.08 ft
Answer:
Step-by-step explanation:
We are looking for what number times .50 makes the equation true.
So, just do backwards equation:
Thus, meaning that what multiplied by 0.50 is equal to 17?
[tex]0.50 * 34[tex]
[tex]==> 17[tex]
