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AleksandrR [38]
3 years ago
13

Please tell fast plzzzzzzz​

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0

Answer:

\huge\boxed{\sf k = 2}

Step-by-step explanation:

Coordinate = (x,y) = (2k-1,k)

<u>This means that:</u>

x = 2k - 1 and y = k

Put it in the <u>given equation: 5x - 4y = 7</u>

5(2k-1) - 4k = 7

10k - 5 - 4k = 7

6k - 5 = 7

Adding 5 to both sides

6k = 7+5

6k = 12

Divide both sides by 6

k = 2

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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Does (3,-2) lie on the on the equation r=(2,1) + t (1,-3)
SIZIF [17.4K]

No, the point (3,-2) does not lie on the on the equation r=(2,1) + t (1,-3).

<h3>What is a straight line? </h3>

It is the minimum distance shown between two extremes points with no curves. It is of infinite length when the extremes points are at infinite distance.

Given extremes points:

r(2,1) and t(1,-3)

The equation of the line becomes:

(y - y_{2} ) = \frac{y_{2} - y_{1}  }{x_{2} - x_{1} } (x - x_{2} )

(y - (-3) ) = \frac{-3 - 1  }{1 - 2 } (x - 1 )

(y + 3 ) = \frac{ -4 }{-1 } (x - 1 )

(y + 3 ) = 4 (x - 1 )\\y = 4x - 4 -3\\y = 4x -7

y - 4x + 7 = 0

Now put the given point (3, -2) and check whether it satisfices the line equation or not:

-2 - 4(3) + 7 = -7 ≠ 0

Hence the line equation is not satisfices, RHS and LHS are different, therefore the point (3, -2) not lie on the given equation.

To learn more about straight line, refer to the link:

brainly.com/question/27560536

#SPJ1

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