There is a 60 minute gap between the two clocks.
These 60 minutes result of a 1 min advance in one for each hour and a 2 min loss in the other.
if we are going 2 mins back and 1 min in
We have a 3 min gap/hour
then to reach a 1 hour gap we would need to go for 2+1+2+1+2+1+2....(20 hours)
since each 3 represent an hour,
to get 60 min gap>60/3=20 hours
Take clock 1 for example, which read 12:00, in reality the time is (12:00-20 minutes)=11:40
or
Take clock 2 for example, which read 11:00, in reality the time is (11:00+20×2 minutes)=11:40
Now go back 20 hours from that;
11:40-20=00:40-9=15:40
There's ur answer 15:40 :)
Answer:
Step-by-step explanation:
Multiply each term of the first polynomial with the second polynomial. Then combine the like terms.
(3a<em>² + 5a - 2)* (5a² -3a + 4)</em>
<em> = 3a² *(5a² -3a + 4) + 5a*(5a² -3a + 4) - 2*(5a² -3a + 4)</em>
<em>=3a²*5a² - 3a*3a² + 4*3a² + 5a*5a² - 3a*5a + 4*5a + 5a²*(-2) - 3a*(-2) + 4*(-2)</em>
<em>=15a⁴ - 9a³ + 12a² + 25a³ - 15a² + 20a - 10a² + 6a - 8</em>
<em>= 15a⁴ </em><u><em>- 9a³ + 25a³</em></u><em> +</em><u><em> 12a² - 15a² - 10a²</em></u><em> +</em><u><em> 20a +6a </em></u><em>- 8</em>
<em>= 15a⁴ + 16a³ - 13a² +26a - 8</em>
Answer: 12
Step-by-step explanation:
since it’s isosceles, the bottom two angles are equal so just subtract 156 from 180 and then divide that by 2.
Okay what’s the question ?
The sum of -3 and a number equal to -91 is -88
