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Fantom [35]
2 years ago
5

Which of the following is most likely the next step in the series?

Mathematics
1 answer:
S_A_V [24]2 years ago
5 0

⁺˚*・༓☾✧.* ☽༓・*˚⁺‧

❀ \huge\underline{ \underline{ \text{Answer :-}}}

➺ It's likely to be <u>option D.</u>

\underbrace{ \overbrace{ \mathfrak{Explanation}}}

➺ The first figure has a line which divides the circle ⭕ into 2 parts. The 2nd figure divides the circle ⭕ into 3 parts while the 3th figure divides the circle ⭕ into 4 parts. Obviously, the 4th figure then should divide the circle ⭕ into 5 parts. Checking all the given options,

  • Option A. doesn't divide the circle ⭕ into any parts.
  • Option B. divides the circle ⭕ into 3 parts
  • Option C. divides the circle ⭕ into 4 parts.
  • <u>Option D. divides the circle ⭕ into 5 parts.</u>

⟹ So, <u>option D.</u> is the correct answer.

⁺˚*・༓☾✧.* ☽༓・*˚⁺‧

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ ツ

꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐

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6 0
2 years ago
Bottles of mango juice are assumed to contain 275 milliliters of juice. There is some variation from bottle to bottle because th
pentagon [3]

Answer:

Step-by-step explanation:

The mean of the set of data given is

Mean = (275.4 + 276.8 + 273.9 + 275.0 + 275.8 + 275.9 + 276.1)/7 = 275.56

Standard deviation = √(summation(x - mean)^2/n

n = 7

Summation(x - mean)^2 = (275.4 - 275.56)^2 + (276.8 - 275.56)^2 + (273.9 - 275.56)^2 + (275.0 - 275.56)^2 + (275.8 - 275.56)^2 + (275.9 - 275.56)^2 + (276.1 - 275.56)^2 = 5.0972

Standard deviation = √(5.0972/7) = 0.85

We would set up the hypothesis test.

For the null hypothesis,

µ = 275

For the alternative hypothesis,

µ ≠ 275

This is a 2 tailed test.

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 7

Degrees of freedom, df = n - 1 = 7 - 1 = 6

t = (x - µ)/(s/√n)

Where

x = sample mean = 275.56

µ = population mean = 275

s = samples standard deviation = 0.85

t = (275.56 - 275)/(0.85/√7) = 1.74

We would determine the p value using the t test calculator. It becomes

p = 0.132

Because the p-value of 0.132 is greater than the significance level of 0.05, we would fail to reject the null hypothesis. We conclude the data does not provide convincing evidence that the mean amount of juice in all the bottles filled that day differs from the target value of 275 milliliters.

8 0
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