Answer:
For the first one its: Volume = 402.12in³
For the second one its: Volume = 201.0619 in³
Step-by-step explanation:
For the first one work:
Volume = 3.1416 x 42 x 8
= 3.1416 x 16 x 8
For the second one work:
Volume = 3.1416 x 42 x 4
= 3.1416 x 16 x 4
Answer:
Option C, 14/21=9/21 is the proportion.
Step-by-step explanation:
Given:
a.5/7 = 10/12
b.9/15 = 12/18
c.4/6 = 8/12
d.14/21 = 9/12
We have to find the proportions.
In proportion two ratios are equal, as it has an equality sign in between so both side must be of same ratio in its simplest form.
Let's work with option C
⇒ 
To find the simplest form we have to divide the numerator and denominator with same digit (or its factor).
Simplest form of
=
,
= 
Simplest form of
= 
Both sides in option C have equal ratios of 2/3.
So 4/6=8/12 is in proportion.
Answer:
The mass of the ice block is 2116 grams ⇒ a
Step-by-step explanation:
The formula of density is
, where m is the mass and V is the volume
To find the mass from this formula multiply both sides by V,
then m = p.V
∵ The density of ice is approximately 0.92 g/cm³
∴ p = 0.92
- That means the mass of 1 cm³ is 0.92 g
∵ The volume of an ice block is 2300 cm³
∴ V = 2300
- Use the formula of the mass
∵ m = p.V
- Substitute the values of p and V in it
∴ m = (0.92)(2300)
∴ m = 2116 grams
The mass of the ice block is 2116 grams
Answer:
8.885
Step-by-step explanation:
Given that :
Sample size, n = 10
The average range, Rbar for all samples = 5
The upper control limit, UCL for the R-chart is :
UCL L= D4Rbar
From the control chart constant table, D4 = 1.777
Hence,
UCL = 1.777 * 5
UCL = 8.885
The UCL for the R-chart is 8.885
You want to find the value of x for which the area under the curve to the left of x is 0.6. One way to do that is to create the cumulative distribution function (CDF) for the given PDF, then see where it is equal to 0.6.
Doing that, we find a = 5.