Hello :
the normal vector of the plane is : d' = [4,-1,5]...(vector perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
<h2><u>Graphing</u></h2>
<h3>The graph of this function is shifted 7 units right and shifted 5 units up.</h3>
<h3>f(x) = -2/3(x - 7)² - 5</h3>
<u>Answer:</u>
<u>Explanation:</u>
- Why false? As I noticed, in the equation f(x) = -2/3(x - 7)² - 5, the vertex is (7, -5). The value of a, which is -2/3, is negative. So the graph opens downwards. The graph shifts 7 units to the right, which is correct, but graphing 5 units up is wrong. Why? 5 is negative, so it should be shifted 5 units down.
Wxndy~~
Answer:
2
Step-by-step explanation:
it literally doubles in size
Expanded FormFind the Expanded Forms of:
Answer:
Standard Form:
7.362
Expanded forms can be written
like a sentence or stacked for
readability as they are here.
Expanded Numbers Form:
7 + 0.3+ 0.06+ 0.002
Expanded Factors Form:
7 ×1 +3 × 0.1+6 × 0.01+2 × 0.001
Expanded Exponential Form:
7 × 100+3 × 10-1+6 × 10-2+2 × 10-3
Word Form:
seven and
three hundred sixty-two thousandths
