<em>Answer:
</em>
<em>
</em>
<em>His March Earnings is $20000
</em>
<em>
</em>
<em>
</em>
<em>Step-by-step explanation:
</em>
<em>
</em>
<em>Given
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Required
</em>
<em>
</em>
<em>Determine the monthly sales
</em>
<em>
</em>
<em>
</em>
<em>Represent the monthly sales with x
</em>
<em>
</em>
<em>The march earnings can be determined using:
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Substitute values of March Earnings and Salary
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Solve for 0.05x
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Solve for x
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>
</em>
<em>Hence:
</em>
<em>
</em>
<em>His March Earnings is $20000</em>
Given that t<span>he expression

represents the total length across the front of the mansion. Let the length of side I be a, then

</span>
Answer:
Interval of 50 on both axis
Step-by-step explanation:
Given





There are several ways to do this, but I will use the observation method, since the dataset is small.
Considering the x-coordinates

Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the x-axis
Considering the y-coordinates

Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the y-axis
<em>So, an interval of 50 can be used on both axes</em>
Answer:
112 years ago
Step-by-step explanation:
38 => 14 yrs
DIfference: 24 yrs
n=8(14)
n=112
Therefore, 112 years ago
500 because in a normal distribution 50% of the total falls below the mean