All categories

2 years ago

What is the value of x in the equation (5^x)^5=5^35

1 answer:

6 0

$\bf (5^x)^5=5^{35}\implies 5^{x\cdot 5}=5^{35}\impliedby \begin{array}{llll} \textit{same bases}\\ \textit{same exponents} \end{array}\implies 5x = 35 \\\\\\ x = \cfrac{35}{5}\implies x=7$

You might be interested in

Use the standard deviation values of the two samples to find the standard deviation of the sample mean differences.

larisa86 [58]

The standard deviation of the sample mean differences is 4.854

<h3>How to determine the standard deviation of the sample mean differences?</h3>

The table of values is given as:

<u>Sample Standard deviation</u>

Red box 3.868

Blue box 2.933

The standard deviation of the sample mean differences is calculated using:

$\sigma = \sqrt{\sigma_1^2 + \sigma_2^2}$

This gives

$\sigma = \sqrt{3.868^2 + 2.933^2}$

Evaluate the expression

$\sigma = 4.854$

Also, the table of value do not give any information regarding the sample size.

This means that the sample size of the session regarding the number of people would purchase the red box and the blue box are unknown

Hence, the standard deviation of the sample mean differences is 4.854

Read more about standard deviation at:

brainly.com/question/15858152

#SPJ1

8 0

1 year ago

What are the next two numbers in this pattern? 5, –30, 180, –1080, . . .

Amiraneli [1.4K]

6480 is the next one, and the second next one is -38880. You can determine this by multiplying the number twice by 36.

4 0

2 years ago

Read 2 more answers

2. R(1, 1), 5(1,7), Т(5,7), U(5, 1); k =<br> 45<br> у<br> о<br> Help

Gekata [30.6K]

(5,7) because when you divide that’s the answer you get

8 0

2 years ago

When an object is thrown upwards with a speed of 64 ft/sec, its height above the ground is given by the function h(t)=−16t2+64t

Svet_ta [14]

Answer:

The object will reach its highest point 0.5 seconds after it has been thrown.

Step-by-step explanation:

The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:

$v(t) = \frac{d}{dt}h(t)$ (1)

Where $v(t)$ is the velocity of the object at time $t$ , in feet per seconds.

If we know that $h(t) =-16\cdot t^{2}+64\cdot t$ and $v(t) = 0\,\frac{ft}{s}$ , then the time when object reaches its highest point is:

$v(t) = -32\cdot t+64$

$-32\cdot t + 64 = 0$

$t = 0.5\,s$

The object will reach its highest point 0.5 seconds after it has been thrown.

3 0

2 years ago

A cylinder has a radius of 24 m and a height of 9 m, what is exact volume of the cylinder

bixtya [17]

Is there anything to choose from

3 0

2 years ago

Read 2 more answers