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Irina-Kira [14]
3 years ago
9

Tank #1 had 200 gallons in it and losing 2 gallons each minute. Tank #2 has 60 gallons in it. How long will it take for both tan

ks to have the same amount of water in them?
Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0

Answer:

  70 minutes

Step-by-step explanation:

Tank 1 must lose 140 gallons to have as much as Tank 2. It will take ...

  (140 gal)(2 gal/min) = 70 min

for the tanks to have the same volume.

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3 0
2 years ago
(40 POINTS)
34kurt

Answer:

1.   y= 25400(1 + 0.11)^x

2.  2019

Step-by-step explanation:

1. y = a(1 + r)^x       <em> </em>

<em>(exponential growth formula :</em>

<em>a = initial value (the amount before measuring growth or decay) </em>

<em>r = growth or decay rate (usually represented as a percentage and expressed as a decimal) </em>

<em> x = number of time units that have passed)</em>

y= 25400(1 + 0.11)^x

so in 1 year, in 1996, we would say

y=25400(1+0.11)^1

y=25400(1.11)

y=28194

2. I found the answer by plugging in numbers into x

with x = 24

y= 25400(1+0.11)^24

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so in 24 years, the population will surpass 302438 which would be 1995+24= 2019

3 0
3 years ago
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