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aev [14]
3 years ago
12

A large cylindrical cooler is 2 (1 )/2 feet high and has a diameter of 1 1/2 feet. It is filled

Mathematics
1 answer:
Mrac [35]3 years ago
6 0
\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad 
\begin{cases}
r=radius=\frac{diameter}{2}\\
h=height\\
----------\\
diameter=1\frac{1}{2}\\\\
r=\cfrac{1\frac{1}{2}}{2}\\\\
h=2\frac{1}{2}
\end{cases}

so.. get the full volume of the cooler, by plugging in the given values

now, the cooler is only filled 3/4, how much is 3/4 of that? well, let's say you got a value V, 3/4 of that is , well \bf \cfrac{3}{4}\cdot  V
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Explain how you compared the fractions in Exercise 9
natima [27]

that question doesnt make sense!

6 0
3 years ago
Find parametric equations and symmetric equations for the line of intersection of the given planes. x + y + z = 5, x + z = 0
oee [108]

The next set is the parametric equations of the same line .

x = t, y = 5 and z = -t .

What is the meaning of parametric and non parametric?

  • The assumptions behind parametric statistics relate to the population's distribution from which the sample was drawn.
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x + y + z = 5, x + z = 0

the line satisfies

x + z = 0 , y = 5

thus

x = t, y = 5 and z = -t .

the first one is technically already the symmetric equations of the line.

thus:

x = -z ; y = 5

the next set is the parametric equations of the same line .

x = t, y = 5 and z = -t .

Learn more about parametric equations

brainly.com/question/12718642

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4 0
1 year ago
Factorise completely:<br> 1. 3xy - x<br>2. 4a² - 9​
Amanda [17]

Answer:

x(3y - 1) and (2a - 3)(2a + 3)

Step-by-step explanation:

(1)

3xy - x ← factor out x from each term

= x(3y - 1)

(2)

4a² - 9 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

4a² - 9

= (2a)² - 3²

= (2a - 3)(2a + 3)

6 0
2 years ago
Solve for a .5(a+b)h
Alla [95]

Answer: 5ah+5bh

Step-by-step explanation:

all i did was foil! hope that helps!

4 0
3 years ago
CAN SOMEONE GIVE ME THE STEPS I HAVE THE ANSWERS I JUST NEED THE STEPS
natali 33 [55]

Problem 1:

1) 3/5x-1 x 3/4=9/10

3x/5-1 x 3/4=9/10

2) 3x/5-1 x 3/4=9/10

3x/5-3/4=9/10

3) 3x/5-3/4=9/10

+3/4 +3/4

4) 3x/5=33/20

5) 5 x 3x/5= 5 x (33/20)

6) 3x=33/4

7) 3x=33/4

/3 /3

8) x=11/4

Problem 2:

1) 6/7+2/5x=-4/5

6/7+2x/5=-4/5

2) 6/7+2x/5=-4/5

-6/7 -6/7

3) 2x/5= --58/35

4) 5 x 2x/5= 5 x (--58/35)

5) 2x= --58/7

6) 2x= --58/7

/2 /2

x= --29/7

3 0
3 years ago
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