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taurus [48]
3 years ago
5

Determine whether the function is continuous or discontinuous:

Mathematics
1 answer:
svet-max [94.6K]3 years ago
4 0

Answer:

The function is discontinuous ad x=0

It has an infinite discontinuity

Step-by-step explanation:

First we need to take a look at the domain. We can see that the function is not defined for x=0. So next we need to determine how the function behaves around x=0, so we can find the lateral limits:

\lim_{x \to 0^-} \frac{x+1}{x} = - \infty

\lim_{x \to 0^+} \frac{x+1}{x} = \infty

You can calculate these limits by using tables and values close to 0 from the left and from the right.

We can see that the function approaches -infinity as it approaches zero from the left and it approaches positive infinicty as it approches to zero from the right. Therefore it has an infinite discontinuity.

This discontinuity can be seen in the attached graph.

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Answer:

Step-by-step explanation:

↔Start of with your 'solution section' to make sure you have the right things↔

↔Solution 1 ➡ 4(x) + 9(y) = 16  

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▪Looking for the value of the 'x'-intercept ⬇▪

◾4 (3) (y) / 2 + 4/ 3 + 9(y) = 16  

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◾Looking for value of the 'y'-intercept ◾

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◾y-intercept : 45

 ◾x = 3(y)/2+4/3 which is translated to this, am i correct? ➡ (y) = 32/45

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↪ Now, we have finally found both of their intercept ⬇

↪x-intercept: 12

↪y-intercept: 5

↪Or you can even say the intercepts in other words. Here's what I am talking about if in case you don't know what I am saying

↪x-intercept: 32✅

↪y-intercept✅

6 0
3 years ago
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Step-by-step explanation:

Hope this helpfull..but if it's not,im so sorry

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Step-by-step explanation:

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