Answer:
Step-by-step explanation:
So I'm assuming when you typed "log yhat=.4785 + 1.468x", you meant to write: . And generally a logarithm can be written in the form
which can then be rewritten as
, but since the log has no base, it's assumed to be 10. So in this case you have the equation:
, which can then be written in exponential form as:
Answer:
The 2nd option is correct.
i.e.
y = 10+1, because the rate of change of the graphed function is 3.
Step-by-step explanation:
From the graph,
Taking two points
Finding the rate of change or slope between (0, 0) and (3, 9)
Using the formula
Rate of change = Slope = m = [y₂ - y₁] / [x₂ - x₁]
= [9 - 0] / [3 - 0]
= 9 / 1
= 3
Thus, the rate of change or slope of the line = m = 3
The slope-intercept form of the line equation
where
Considering the function in 2nd option
y = 10x+1
Comparing with the slope-intercept form of the line equation y = mx+b
The rate of change or slope = m = 10
Conclusion:
The rate of change or slope of the graphed line: m = 3
The rate of change or slope of y = 10x+1 is: m = 10
Thus, the rate of change of y = 10x+1 i.e. m = 10 is greater than the rate of change of the graphed line i.e. m = 3.
Hence, the 2nd option is correct.
i.e.
y = 10+1, because the rate of change of the graphed function is 3.