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sineoko [7]
3 years ago
8

Complete the statement to describe the expression abc + defabc+defa, b, c, plus, d, e, f. The expression consists of terms, and

each term contains factors.
Mathematics
1 answer:
natita [175]3 years ago
3 0

Answer:

The expression consists of 2 terms and each terms contains 3 factors.

Step-by-step explanation:

Given the expression (abc)+(def), the description of the expression is as shown:

The expression consists of 2 terms and each terms contains 2 factors.

Terms are expressions connected by mathematical signs such as addition and subtraction sign. As we can see from (abc)+(def), 'abc' and 'def' are separated by addition signs therefore both abc and def are the "terms" of the expression.

Factors are variables connected using the multiplication or bracket signs. As we can see, each term contains 3 factors. Looking at the first term 'abc', we can see that there are 3 variables/factors (a, b and c) multiplied together. This shows that they are connected by multiplication signs and same goes with 'def'.

Hence, the expression consists of 2 terms and each terms contains 3 factors.

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There are 44 oranges in the box

Step-by-step explanation:

4.29 kg = 4290 g

4290g / 97.5 g = 44

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What is the number of diagonals that intersect at a given vertex of a hexagon, heptagon, 30-gon and n-gon?
DENIUS [597]

Answer:

i. 9

ii. 14

iii. 405

iv. \frac{n(n-3)}{2}

Step-by-step explanation:

The number of diagonals in a polygon of n sides can be determined by:

\frac{n(n-3)}{2}

where n is the number of its sides.

i. For a hexagon which has 6 sides,

number of diagonals = \frac{6(6-3)}{2}

                                   = \frac{18}{2}

                                   = 9

The number of diagonals in a hexagon is 9.

ii. For a heptagon which has 7 sides,

number of diagonals = \frac{7(7-3)}{2}

                                   = \frac{28}{2}

                                   = 14

The number of diagonals in a heptagon is 14.

iii. For a 30-gon;

number of diagonals = \frac{30(30-3)}{2}

                                          = \frac{810}{2}

                                         = 405

The number of diagonals in a 30-gon is 405.

iv. For a n-gon,

number of diagonals = \frac{n(n-3)}{2}

The number of diagonals in a n-gon is \frac{n(n-3)}{2}

7 0
3 years ago
Jamie is investing $47,000 in an account paying 9.26% interest compounded continuously. What will Jamie's account balance be in
frutty [35]

Answer:

7398740

Step-by-step explanation:

17*9.26=157.42

please give me brainliest

47,000 *157.42

7398740

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3 years ago
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