Answer:
D
Step-by-step explanation:
Given
f(x) = ← cancel (x + 2) on the numerator/ denominator
This creates a discontinuity ( a hole ) at x = - 2
f(x) =
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
x - 3 = 0 ⇒ x = 3 ← excluded value
Thus domain is { x | x ≠ - 2, 3 } → D
Given:
A number is 400.
To find:
The additive inverse of 400.
Solution:
We know that the sum of a number and its additive inverse is 0.
If "a" is number and "b" is its additive inverse, then
Let x be the additive inverse of 400. Then,
Subtract both sides by 400.
Therefore, the additive inverse of 400 is .
Answer:
Solution : (15, - 11)
Step-by-step explanation:
We want to solve this problem using a matrix, so it would be wise to apply Gaussian elimination. Doing so we can start by writing out the matrix of the coefficients, and the solutions ( - 5 and - 2 ) --- ( 1 )
Now let's begin by canceling the leading coefficient in each row, reaching row echelon form, as we desire --- ( 2 )
Row Echelon Form :
Step # 1 : Swap the first and second matrix rows,
Step # 2 : Cancel leading coefficient in row 2 through ,
Now we can continue canceling the leading coefficient in each row, and finally reach the following matrix.
As you can see our solution is x = 15, y = - 11 or (15, - 11).