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Reptile [31]
3 years ago
12

Once again assistance is needed. Help!!!!

Mathematics
2 answers:
tatiyna3 years ago
8 0

Answer:

D

Step-by-step explanation:

hope this helps

snow_lady [41]3 years ago
5 0

Answer:

D

Step-by-step explanation:

Given

f(x) = \frac{(x+2)(x-1)}{(x-3)(x+2)} ← cancel (x + 2) on the numerator/ denominator

This creates a discontinuity ( a hole ) at x = - 2

f(x) = \frac{x-1}{x-3}

The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.

x - 3 = 0 ⇒ x = 3 ← excluded value

Thus domain is { x | x ≠ - 2, 3 } → D

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S+f=24 s=3f<br><br> I need this now
scoundrel [369]

Answer:

f=6 and s=18

Step-by-step explanation:

Let's solve your system by substitution.

s+f=24;s=3f

Rewrite equations:

s=3f;f+s=24

Step: Solves=3ffor s:

s=3f

Step: Substitute3fforsinf+s=24:

f+s=24

f+3f=24

4f=24(Simplify both sides of the equation)

4f

4

=

24

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(Divide both sides by 4)

f=6

Step: Substitute6forfins=3f:

s=3f

s=(3)(6)

s=18(Simplify both sides of the equation)

Answer:

f=6 and s=18

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