Once again assistance is needed. Help!!!!
2 answers:
Answer:
D
Step-by-step explanation:
Given
f(x) = ← cancel (x + 2) on the numerator/ denominator
This creates a discontinuity ( a hole ) at x = - 2
f(x) =
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
x - 3 = 0 ⇒ x = 3 ← excluded value
Thus domain is { x | x ≠ - 2, 3 } → D
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Answer:
13) ⇒
15) ⇒
Step-by-step explanation:
Given expression:
13)
15)
Write the expressions in radical form.
Solution:
For an expression with exponents as fraction like
the numerator represents the power it is raised to and the denominator
represents the nth root of the expression.
For an expression with exponents as negative fraction like
We take the reciprocal of the term by rule for negative exponents.
So it is written as:
using the above properties we can write the given expressions in radical form.
13)
⇒ [Using rule of negative exponents]
⇒ [writing in radical form]
15)
⇒ [Since 2nd root is given as
in radical form]