Once again assistance is needed. Help!!!!
2 answers:
Answer:
D
Step-by-step explanation:
Given
f(x) = ← cancel (x + 2) on the numerator/ denominator
This creates a discontinuity ( a hole ) at x = - 2
f(x) =
The denominator of f(x) cannot be zero as this would make f(x) undefined. Equating the denominator to zero and solving gives the value that x cannot be.
x - 3 = 0 ⇒ x = 3 ← excluded value
Thus domain is { x | x ≠ - 2, 3 } → D
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