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3 years ago

8

Yesterday Clara reached 4 people in 10 phone calls while Toby reach three people in 8 phone calls if they continue at this rate

who will reach more people in 40 phone calls

1 answer:

SashulF [63]3 years ago

8 0

Answer:

Clara will reach more people in 40 phone calls.

Step-by-step explanation:

If Both of them had 40 phone calls you would divide 40 phone calls to how much they actually had. In this case for Clara it's 40 divided by 10 which is 4, And then you have to multiply 4x4 which is 16. For Toby He had to divide 40 by 8 which is 5, and then multiply 3x5 which is 15. Therefore Clara had reached more phone calls then Toby.

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Consider the following hypothesis test:H 0: = 17H a: 17A sample of 40 provided a sample mean of 14.12. The population standard d

Nonamiya [84]

Answer:

We conclude that the population mean is not equal to 17.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 17

Sample mean, $\bar{x}$ = 14.12

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 4

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 17\\H_A: \mu \neq 17$

We use Two-tailed z test to perform this hypothesis.

a) Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{14.12 - 17}{\frac{4}{\sqrt{40}} } = -4.5536$

b) P-value can be calculated from the standard z-table.

P-value = 0.0000

c) Since the p-value is less than the significance level, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17

d) Now, $z_{critical} \text{ at 0.05 level of significance } = \pm 1.96$

e) Rejection Rule:

We reject the null hypothesis if it is less than lower critical value and greater than the upper critical value

If the z-statistic lies outside the acceptance region which is from -1.96 to +1.96, we reject the null hypothesis.

f) Since the calculated z-stat lies outside the acceptance region, we reject the null hypothesis and accept the alternate hypothesis. Thus, the population mean is not equal to 17.

4 0

3 years ago

If 2/x+ 3/y =13 and 5/x- 4/y = -2, then x+y equals

creativ13 [48]

Answer:

$x + y = \frac{5}{6}$

Step-by-step explanation:

Let:

$u = \frac{1}{x} \\ v = \frac{1}{y}$

This allows us to manipulate the equations like we normally would.

$2u + 3v = 13 \\ 5u - 4v = - 2 \\ \\ + 8u + 12v = 52 \\ + 15u - 12v = - 6 \\ 23u = 46 \\ u = 2 \\ \\ 2(2) + 3v = 13 \\ 4 + 3v = 13 \\ 3v = 9 \\ v = 3$

Then, we return the values where they belong.

$u = \frac{1}{x} \\ 2 = \frac{1}{x} \\ x = \frac{1}{2} \\ \\ v = \frac{1}{y} \\ 3 = \frac{1}{y} \\ y = \frac{1}{3}$

Finally, we add:

$\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}$

7 0

3 years ago

A sample of 16 ATM transactions shows a mean transaction time of 67 seconds with a standard deviation of 12 seconds. State the h

Soloha48 [4]

Answer:

Null hypothesis: $\mu \leq 60$

Alternative hypothesis: $\mu > 60$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33$

Step-by-step explanation:

Data given and notation

$\bar X=67$ represent the sample mean

$s=12$ represent the population standard deviation for the sample

$n=16$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 60, the system of hypothesis would be:

Null hypothesis: $\mu \leq 60$

Alternative hypothesis: $\mu > 60$

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{67-60}{\frac{12}{\sqrt{16}}}=2.33$

4 0

3 years ago

29 plus x Equals 90 im a lil smart so ntm

solniwko [45]

$29 + x = 90 \\ x = 61$

5 0

4 years ago

62-9.817 <br>BTW ITS AN DECIMAL.

Basile [38]

62.000
-9.817
---------
52.183

5 0

3 years ago