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Nataly [62]
3 years ago
9

The table below gives the age and bone density for five randomly selected women. Using this data, consider the equation of the r

egression line for predicting a woman's bone density based on her age. Note: The correlation coefficient may or may not be statistically significant for the data given. In practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.Age 35 42 45 66 67
Bone Density356 339 338 323 315The following scatterplot is for your information:Bone Density Scatterplot (2)Question 1: Use the equation of the regression line for predicting a woman's bone density based on her age. (round to 2 decimals).Question 2: Enter the estimated value of y when x = 43 (round to 2 decimals).Question 3: Substitute the values you found in steps 1 and 2 into the equation for the regression line (or find the regression equation in the session output) to find the estimated linear model. According to this model, if the value of the independent variable is increased by one unit, then find the change in the dependent variable y (round to 2 decimals).Question 4: Enter the estimated value of y when x = 43 (round to 2 decimals).Question 5: Enter the error prediction when x = 43 (round to 2 decimals).Question 6: Enter the value of the coefficient of determination (as a decimal, not a percentage) and round to 2 decimals.Question 7: Enter the p-value for the regression model (round to 3 decimals)Question 8: Based on the p-value, I would consider the given model in making predictionsA) True B) False C) There is not enough information to make a decision.

Mathematics
1 answer:
tatiyna3 years ago
7 0

Answer:

Step-by-step explanation:

find the solution below

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Minchanka [31]

Answer: C

Step-by-step explanation: Hope this help :D

4 0
3 years ago
Read 2 more answers
Find m∠I. Put the answer below.<br> m∠I =
pashok25 [27]

Answer:

The answer is 68°

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • A right angled-triangle IGH.
  • where, m∠G = 90°
<h3><u>To </u><u>Find</u>;</h3>
  • m∠I = ?

We know that

tan θ = Opp ÷ Adj

tan θ = 5 ÷ 2

tan θ = 2.5

tan θ = 68.2 ≈ 68

We know that tan 68 = 2.5

Thus, The m∠I is 68°

<u>-TheUnknownScientist 72</u>

5 0
2 years ago
Three of the choices are ways to express 0.50. Which is NOT?
Ganezh [65]

Option B

5 hundredths is not the way to express 0.50

<h3><u>Solution:</u></h3>

Given that Three of the choices are ways to express 0.50

To find: wrong option

Let us first write 0.50 in different ways

<h3><em><u>To convert a Decimal to a Fraction follow these steps: </u></em></h3>

Step 1: Write down the decimal divided by 1, like this: decimal 1.

Step 2: Multiply both top and bottom by 10 for every number after the decimal point. ...

Step 3: Simplify (or reduce) the fraction.

\rightarrow 0.50 = \frac{0.50 \times 100}{100} = \frac{50}{100}

\frac{50}{100} means 50 hundredths

<h3>Therefore option D is correct</h3>

On simplifying \frac{50}{100} we can write,

\rightarrow \frac{50}{100} = \frac{5}{10} = \frac{1}{2}

\frac{1}{2} means one half

<h3>Therefore option A (one half) is correct</h3>

Similarly, \frac{5}{10} means 5 tenths

<h3>Therefore Option C is also correct</h3>

Thus the wrong option is B

<em><u>Justification:</u></em>

5 hundredths can be written as:

\frac{5}{100} = 0.05

Therefore option B is wrong

5 0
2 years ago
Which choice best represents the balance of a savings account at the end of 6 years if the simple interest earned each year is 6
Amiraneli [1.4K]

Answer:

$507.00.

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 6.5%/100 = 0.065 per year,

then, solving our equation

I = 1300 × 0.065 × 6 = 507

I = $ 507.00

The simple interest accumulated

on a principal of $ 1,300.00

at a rate of 6.5% per year

for 6 years is $ 507.00.

4 0
2 years ago
*I WILL MARK U BRANLIEST AND GIVE 40 POINTS IF U ANSWER ALL THREE*
Gnesinka [82]

Step-by-step explanation:

1. 18(5)=90           18(6)=108

90*108= 9720

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2. 1/2+1/2= 1      1/2=4 ft

The pole is 8 feet tall

3. 3 feet

3 0
3 years ago
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