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arlik [135]
3 years ago
12

I report if u guess. A 98% confidence interval for a proportion is found to be (0.32, 0.38). What is the sample proportion?

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Sample proportional is right at the centre of the interval

p = (0.32+0 38)/2

0.7/2

0.35

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3 years ago
Read 2 more answers
Could someone help me with this?
hodyreva [135]

Step-by-step explanation:

Identity the variable:

Initial Velocity is 35.

Initial Height is 204

Final Height is 0.

What looking for the time.

So we have

0 =  - 16 {t}^{2}  + (35)t + 204

Use Quadratic Formula,

- b± \frac{ \sqrt{b {}^{2}  - 4ac} }{2a}

A is -16, B is 35 , C is 204.

So we have

- 35± \frac{ \sqrt{ {35}^{2} - 4( - 16)(204) } }{ - 32}

- 35± \frac{ \sqrt{1225 + 2240}  }{ - 32}

- 35± \frac{ \sqrt{3465} }{ - 32}

{35}  ± \frac{ \sqrt{3465} }{ - 32}

The positve solution is

4.83

So the answer is 4.83 seconds

5 0
2 years ago
Need help with problem, been stuck on it for a while
Alinara [238K]
Well, if you look at the picture, the "radius" is 1/4, so r = 1/4.

\bf \textit{diameter of a circle}\\\\&#10;d= 2r\qquad \boxed{r=\frac{1}{4}}\implies d=2\cdot \cfrac{1}{4}\implies d=\cfrac{1}{2}\\\\&#10;-------------------------------\\\\&#10;\textit{circumference of a circle}\\\\&#10;C=2\pi r\qquad \boxed{r=\frac{1}{4}~,~\pi =\cfrac{22}{7}}\implies C=2\left( \frac{22}{7} \right)\left( \frac{1}{4} \right)&#10;\\\\\\&#10;C=\cfrac{2\cdot 22\cdot 1}{7\cdot 4}\implies C=\cfrac{11}{7}\\\\&#10;-------------------------------\\\\

\bf \textit{area of a circle}\\\\&#10;A=\pi r^2\qquad \boxed{r=\frac{1}{4}~,~\pi =\cfrac{22}{7}}\implies A=\left( \frac{22}{7} \right)\left( \frac{1}{4} \right)^2&#10;\\\\\\&#10;A=\cfrac{22}{7}\cdot \cfrac{1^2}{4^2}\implies A=\cfrac{22}{7}\cdot \cfrac{1}{16}\implies A=\cfrac{11}{56}
8 0
4 years ago
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