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STatiana [176]
3 years ago
6

A piece of manufacturing equipment valued at $125000 depreciates at a steady rate of 10% per year. What is the value of the equi

pment in 15 years?
Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

The value of the equipment in 15 years will be $25,736

Step-by-step explanation:

The value of the equipment after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the yearly depreciation rate, as a decimal.

A piece of manufacturing equipment valued at $125000 depreciates at a steady rate of 10% per year.

This means that V(0) = 125000, r = 0.1

Then

V(t) = V(0)(1-r)^{t}

V(t) = 125000(1-0.1)^{t}

V(t) = 125000(0.9)^{t}

What is the value of the equipment in 15 years?

This is V(15).

V(15) = 125000(0.9)^{15} = 25736

The value of the equipment in 15 years will be $25,736

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<em>Assuming you want this rounded to the hundredths.</em>

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Step-by-step explanation:

6. Because these angles are supplementary, they add up to 180 degrees. Using this, we can solve for x.

Step 1: Build your equation

3x + 5 + 4x + 1 = 180

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Step 2: Collecting like terms on one side 1: Subtract 3x from both sides

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Step 3: Collecting like terms on one side 2: Subtract 1 from both sides.

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Step 1: Build your equation.

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Step 2: Combine like terms.

7x + 6 = 90

Step 3: Subtract 6 from both sides of the equation.

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Step 4: Divide the coefficient of x from both sides.

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Step 1: Build your equation.

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Step 3: Subtract 6 from both sides of the equation.

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