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STatiana [176]
3 years ago
6

A piece of manufacturing equipment valued at $125000 depreciates at a steady rate of 10% per year. What is the value of the equi

pment in 15 years?
Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

The value of the equipment in 15 years will be $25,736

Step-by-step explanation:

The value of the equipment after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the yearly depreciation rate, as a decimal.

A piece of manufacturing equipment valued at $125000 depreciates at a steady rate of 10% per year.

This means that V(0) = 125000, r = 0.1

Then

V(t) = V(0)(1-r)^{t}

V(t) = 125000(1-0.1)^{t}

V(t) = 125000(0.9)^{t}

What is the value of the equipment in 15 years?

This is V(15).

V(15) = 125000(0.9)^{15} = 25736

The value of the equipment in 15 years will be $25,736

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Answer:

The answer is

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Step-by-step explanation:

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To find the equation of the parallel line we must first find the slope of the original line

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We have the final answer as

<h3>y =  -  \frac{19}{18} x +  \frac{76}{2}</h3>

Hope this helps you

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