Answer:
Given: In triangle ABC and triangle DBE where DE is parallel to AC.
In ΔABC and ΔDBE
[Given]
As we know, a line that cuts across two or more parallel lines. In the given figure, the line AB is a transversal.
Line segment AB is transversal that intersects two parallel lines. [Conclusion from statement 1.]
Corresponding angles theorem: two parallel lines are cut by a transversal, then the corresponding angles are congruent.
then;
and
![\angle BEC \cong \angle BCA](https://tex.z-dn.net/?f=%5Cangle%20BEC%20%5Ccong%20%5Cangle%20BCA)
Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.
by Reflexive property of equality:
By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar
therefore, by AAA similarity postulates theorem
![\triangle ABC \sim \triangle DBE](https://tex.z-dn.net/?f=%5Ctriangle%20ABC%20%5Csim%20%5Ctriangle%20DBE)
Similar triangles are triangles with equal corresponding angles and proportionate side.
then, we have;
[By definition of similar triangles]
therefore, the missing statement and the reasons are
Statement Reason
3.
Corresponding angles theorem
and
5.
AAA similarity postulates
6. BD over BA Definition of similar triangle
I believe the answer is 1981/1000 x I think
8c + 6-3c -2
8c -3c + 6-2 = 5c + 4
Brainliest please!
Answer:
300
Step-by-step explanation:
Sum the parts of the ratio : 3 + 2 = 5 parts
Divide the number of appointments by 5 to find the value of one part of the ratio, that is
= 100 ← value of 1 part of the ratio
The mums consisted of 3 parts, hence
3 × 100 = 300 ← appointments with mums