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4 years ago

True or false? When n is a negative integer, n-n=0. Justify your response

1 answer:

7 0

This would be true. It is a trick question if you didn't pay attention to the negative. Just try substituting the n s for negative integers. For example:
-4--4. The negatives rule each other out and then -4+4=0.

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A health care organization, StarCare, wants to implement a program to increase use of diabetes care services. In the past StarCa

lions [1.4K]

Answer:

a) The fixed cost is $1350.

b) Total variable cost is $6000.

Step-by-step explanation:

a) The fixed cost = Operational cost + Insurance company bill.

= $ 1000 + 350 = $1350.

b) Variable cost:-

The number of facilitators = 20.

The salary for each facilitator = $300.

Total variable cost = $300 x 20 = $6000.

7 0

4 years ago

Please help! No links! Thanks!!

Readme [11.4K]

Answer: 30

Step-by-step explanation:

3 times 2 is 6 and divided by 2 is 3 and 3 times 10 is 30

5 0

3 years ago

Please:<br> Divide 24 in ratio 3:5

nalin [4]

24/8 = 3

3x3 = 9
5x3=15

so
<span> 24 in ratio 3:5 = 9:15</span>

3 0

3 years ago

The volume of a rectangular prism is 2x^3+9x^2-8x-36 with height x + 2. Using synthetic division, what is the area of the base?

navik [9.2K]

Answer:

Area of the base = $2x^2+5x-18$

Step-by-step explanation:

We know that volume of rectangular prism = (Area of base) x (Height)

or [Area of base] = [Volume]/[Height]

So basically we need to divide given area by given height to find the answer.

given height is (x+2) that means (x+2) must be factor of volume equation

or x=-2 must be root of volume equation so write down coefficients of volume equation then we divide by -2 as shown in attached picture.

Last digit on the right is always remainder.

Remaining coefficients {2, 5, -18} will give the area equation: $2x^2+5x-18$

Hence final answer is:

Area of the base = $2x^2+5x-18$

5 0

3 years ago

Can anyone answer me this question

yuradex [85]

Question 1:

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 3 + 1$

We must find $g_ {o} f (0$ ):

By definition we have to:

$g_ {o} f = g (f (x))\\f_ {o} g = f (g (x))$

$g (f (x)) = (4x + 1) ^ 3 + 1$

We substitute $x = 0$ :

$g (f (0)) = (4 (0) +1) ^ 3 + 1 = 1 ^ 3 + 1 = 2$

So, we have that $g (f (0)) = 2$

Answer:

$g (f (0)) = 2$

Question 2:

For this case we have the following functions:

$f (x) = 4x + 1\\g (x) = x ^ 3 + 1$

We must find $f_ {o} g (0)$ :

By definition we have to:

$f_ {o} g = f (g (x))\\f (g (x)) = 4 (x ^ 3 + 1) + 1 = 4x ^ 3 + 4 + 1 = 4x ^ 3 + 5$

We substitute $x = 0$ :

$f (g (0)) = 4 (0) ^ 3 + 5 = 5$

Answer:

$f (g (0)) = 5$

Question 3:

For this case we must find the inverse of the following function:

$h (x) = \frac {2x + 1} {3}$

To do this, we follow the steps below:

We change y for $h (x)$ :

$y = \frac {2x + 1} {3}$

We exchange variables:

$x = \frac {2y + 1} {3}$

We clear the value of the variable "y":

$3x = 2y + 1\\3x-1 = 2y\\y = \frac {3x} {2} - \frac {1} {2}$

We change y for $h^{ -1} (x)$ :

$h ^{ - 1} (x) = \frac {3x} {2} - \frac {1} {2}$

Answer:

$h ^ {- 1} (x) = \frac {3x} {2} - \frac {1} {2}$

3 0

4 years ago