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castortr0y [4]
3 years ago
8

What is the diagonal of a rectangle with length 48 inches and width 40 inches?

Mathematics
2 answers:
True [87]3 years ago
7 0
Use the Pythagorean Theorem: a^2 + b^2 = c^2
You can do this because when you cut the rectangle in half with the diagonal, it forms a right triangle, making the diagonal the hypotenuse (c). 

40^2 + 48^2 = c^2

1600 + 2304 = c^2

3904 = c^2

\sqrt{3904} =  \sqrt{c^2}

62.48 = c

Diagonal: 62.48 inches

brilliants [131]3 years ago
4 0
I think its D<span>=w<span><span>2</span>+<span>l2</span></span></span><span>=<span><span>402</span>+<span>482</span></span></span><span>≈ <span>62.482<span>in</span></span></span>
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