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ziro4ka [17]
3 years ago
14

High School

Mathematics
1 answer:
Lilit [14]3 years ago
6 0

Answer:

Step-by-step explanation:

6) y = 2x² +  6x - 80

1) y = 2*x² + 2*3x - 2*40

  y = 2 [ x² + 3x - 40]

2) Sum = 3

Product = -40

Factors = (-5) ; 8   {-5 +8 = 3  ; (-5)*8 = -40}

y = 2 [ x² + 8x - 5x - 40]

      = 2 [ x(x + 8) -  5(x + 8) ]

      = 2 [ (x +8) (x - 5)]

y = 2(x +8)(x -5)

b) y = 0

2(x + 8)(X - 5) = 0

x + 8 = 0 ;  x - 5 = 0

x = -8 ;             x = 5

(-8) ; 5  are the zeros.

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Answer this please......
Brrunno [24]

Answer:

1). Option A

2). Option B

Step-by-step explanation:

Question 1

Rule for the dilation of a point by a scale factor 'k' is given by the rule,

(x, y) → (kx, ky)

By this rule image of point A when dilated by the scale factor = 1.25,

A(-12, -8) → A'[(-12 × 1.25), (-8 × 1.25)]

              → A'(-15, -10)

Option A will be the answer.

Question 2

Scale factor = \frac{\text{Dimension or one side of the image}}{\text{Dimension or one side of the preimage}}

From the figure attached,

Scale factor = \frac{F'E'}{FE}

                    = \frac{4}{14}

                    = \frac{2}{7}

Therefore, rule for the dilation of ABC to form image triangle A'B'C' will be,

(x, y) → (\frac{2}{7}x, \frac{2}{7}y)

Option B will be the answer.

8 0
3 years ago
The DJ charges $200 and decorations cost $100. The team decides to charge each student $5.00 to attend the dance. If n represent
diamong [38]
Well if you dont add any decimals then this should start you out. (200+100)- 1500 = n
3 0
3 years ago
What is the area of a semicircle with diameter 8 cm?
garik1379 [7]

Answer:

We'll use 3.14 as an approximation of pi. So, now we plug the values into the equation. A = 3.14 * 8^2/2.

5 0
3 years ago
The distance between the goals on a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.What
Korvikt [17]

Answer:

41.02 meters.

Step-by-step explanation:

See the attached diagram.

The distance between the goals of a soccer field is 52 meters. Each goal has a box that extends 5.49 meters into the field.

If the distance from the front of the box at one end of the field to the front of the box at the other end of the field is x meters, then we can write the equation as

5.49 + x + 5.49 = 52

⇒ x + 10.98 = 52

⇒ x = 41.02 meters. (Answer)

7 0
4 years ago
Let g(x) = − 7x + 4. Find g(2)<br><br> -5<br> -10<br> 18<br> 10
cluponka [151]

Answer:

g (2) = -7 x 2+4

        = -14+4

        = -10

g(-5) = -7 x (-5) +4

        = 35+4=39

g(-10)= -7 x (-10)+4

        =70+4=74

g(18)= -7 x 18+4

      = -126+4

     = -122

g(10)= -7 x 10+4

      = -70+4

      = -66

7 0
3 years ago
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