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allsm [11]
3 years ago
6

What is 2 quarts in 1 pint

Mathematics
2 answers:
Serggg [28]3 years ago
7 0
Pint is half size of a quart, so the conversion factor from pints to quarts is 0.5 (It's the same for fluid and dry measurement).
CaHeK987 [17]3 years ago
6 0
The answer would be if you have 2 quarts in 1 pint then you have half of a pint:

1/2=0.5
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Simplify the expression -4^2(3x - 7)
maxonik [38]

Answer:

−48x+112

Step-by-step explanation:

evatulate: −16  (3−7)

                -48+112

3 0
2 years ago
Drew collins purchased a new treadmill for $1,662. He made 15% down payment and financed the remainder. What amount did he finan
BigorU [14]
Given that Collins made 15% down payment, the amount to be financed will be given by:
(Price of treadmill)-(down payment)
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8 0
3 years ago
Factor each completely.<br><br> 2x3 - 9x2 + 9x
EleoNora [17]

Answer:

x(2x−3)(x−3)

Step-by-step explanation:

2x^3−9x^2+9x

= x(2x−3)(x−3)

4 0
3 years ago
600 miles in 8 hours<br><br> _?_ miles per hour<br><br> (number answer only)<br><br> Question
kow [346]

Answer:

75

Step-by-step explanation:

you have 600 = 8 and you want to break it down into just 1 hour so you divide both sides by 8

600/8 = 75

4 0
3 years ago
Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number
sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

E(X)=\sum x\cdot P(X=x)

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner:   1           2           3          4           5              6

Amount earned (<em>X</em>):   $1        $4         $7        $10     -$8.75     -$8.75

Probability:                 1/6       1/6         1/6        1/6         1/6           1/6

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x\cdot P(X=x)

         =(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})

         =\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}

         =\frac{1+4+7+10-8.75-8.75}{6}

         =0.75

Thus, the expected value of playing the game is $0.75.

5 0
3 years ago
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