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zzz [600]
3 years ago
7

How many positive integers less than or equal to 2000 have an odd number of factors?

Mathematics
1 answer:
Paraphin [41]3 years ago
8 0
All you have to do is count the number of perfect squares less than 200.
Or you can take the square root of 2000 to get 44.721. So 44 Positive integers.
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A drawer contains 4 red socks, 7 white socks, and 11 blue socks. Without looking, you draw out a sock and then draw out a second
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Total socks = 4 + 7+ 11 = 22
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Write all names that apply to 7/8
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2 + 3(x + 2x) = −2x(2 − 4) + 1<br><br> A) −5 <br> B) −<br> 1<br> 5<br> C) 5 <br> D) <br> 1<br> 5
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3 years ago
A company that rents small moving trucks wants to purchase 25 trucks with a combined capacity of 28,000 cubic feet. Three differ
pickupchik [31]

Answer:

We have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks

Step-by-step explanation:

Let the number of 10-foot truck with a capacity of 350 cubic feet purchased=a

Let the number of 14-foot truck with a capacity of 700 cubic feet purchased=b

Let the number of 24-foot truck with a capacity of 1,400 cubic feet purchased=c

The company wants to purchase 25 trucks, therefore.

  • a+b+c=25

Furthermore, the combined capacity of the trucks is 28,000 cubic feet.

  • 350a+700b+1400c=28000

Since the number of equations is less than the number of variables, you can not use a matrix equation to solve this problem.  The solution is most easily found using an augmented matrix.  

The augmented matrix is presented below:  

\left[\begin{array}{ccc|c}1&1&1&25\\350&700&1400&28000\end{array}\right]

Using the calculator, the reduced row echelon form is:

\left[\begin{array}{ccc|c}1&0&-2&-30\\0&1&3&55\end{array}\right]

where  

a- 2c=-30 means a =2c-30

b+3c=55 means b= 55-3c

We alter the value of c as long as neither a nor b becomes negative. Suitable values for c are 15, 16, 17, and 18:

\left|\begin{array}{|c||c||c|}a=2c-30&b=55-3c&c\\0&10&15\\2&7&16\\4&4&17\\6&1&18\end{array}\right|

We can easily  verify that, for each solution, the number of trucks adds up to 25 and the fleet capacity is 28,000 cubic feet.

We therefore have 4 solutions:

  • No 10-foot truck, 10  14-foot trucks, and 15 24-foot trucks
  • 2 10-foot trucks, 7 14-foot trucks, and 16 24-foot trucks
  • 4 10-foot trucks, 4  14-foot trucks, and 17 24-foot trucks
  • 6 10-foot trucks, 1 14-foot trucks, and 18 24-foot trucks
4 0
4 years ago
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