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stealth61 [152]
2 years ago
5

What is the value of t in the following equation? t + 14 = 2712

Mathematics
2 answers:
sergey [27]2 years ago
5 0

Answer:

2698

Step-by-step explanation:

Solnce55 [7]2 years ago
4 0

Answer:

2698

Step-by-step explanation:

2712-14

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cupoosta [38]
The answer is area= 285 cm
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A number divided by three less two is at most two
zheka24 [161]

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6

Step-by-step explanation:

6/3 = 2

5 0
3 years ago
A rectangle has a perimeter of 26 cm and one of its sides has length of 5 cm
otez555 [7]

Answer:5 by 8 by 5 by 8

Step-by-step explanation: the perimeter is 26 and one side if 5 so you know that another side is also 5. So add 5 and 5 together you get 10. Then subtract 10 from the perimeter(witch we know is 26) and you end up with 16. we know that the last two side lengths are the same so divide 16 by two and the sidle length is 8.

8 0
3 years ago
Which is a quadratic function having a leading coefficient of 3 and a constant term of –12? f(x) = –12x2 3x 1 f(x) = 3x2 11x – 1
eimsori [14]

The correct option is b.

<h2>Quadratic Equation</h2>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

<h2>Leading coefficient </h2>

The leading coefficient of an equation is a coefficient of the term having the highest power in the equation.

Given options:

a.)  f(x) = -12x^2+3x+1 \\

b.)  f(x) = 3x^2+11x-12 \\

c.)  f(x) = 12x^2+3x+3\\

d.)  f(x) = 3x -12.

<h3 /><h3>Solution</h3>

As it is given that the leading coefficient of the equation is 3. therefore, the value of the 'a' in the general quadratic equation is 3,

3x²+bx+c,

Also, the value of the constant is -12, therefore, the value of c is -12,

3x²+bx-12

From all the given options the only feasible option is b only.

Hence, the correct option is b.

Learn more about Quadratic Equation:

brainly.com/question/2263981

8 0
2 years ago
Here is a growing pattern of squares:
Flura [38]

Answer:

squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1

Step-by-step explanation:

3 0
1 year ago
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