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kakasveta [241]
3 years ago
10

If x=3 and y=-2 then x2 - xy x²+2y

Mathematics
2 answers:
laila [671]3 years ago
7 0

Answer:

2.4

Step-by-step explanation:

x = 3, y = -2

x2 - xy/x² + 2y

=x2 - xy

=(3)2 - 3 × (-2)

6 - (-6)

= 12

x² + 2y

= 3² + 2(-2)

= 9 + -4

= 5

12/5

= 2.4

Naddika [18.5K]3 years ago
4 0

Answer:

Step-by-step explanation:

(3)*2=6

-

(3)*(-2)=-6

6-(-6)=12

3*3=9

+2(-2)=-4

9+ -4= 5

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ivolga24 [154]
\bf (2x+3)^5\implies 
\begin{array}{llll}
term&coefficient&value\\
-----&-----&-----\\
1&&(2x)^5(+3)^0\\
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\end{array}

as you can see, the terms exponents, for the first term, starts at highest, 5 in this case, then every element it goes down by 1, till it gets to 0

for the second term, starts at 0, and every element it goes up by 1, till it gets to the highest

now, to get the coefficient, they way I get it, is "the product of the current coefficient and the exponent of the first term, divided by the exponent of the second term plus 1"

notice the first coefficient is always 1

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how did we get 10 for the fourth element?  well, 10*2/4


\bf (2x-3y)^4\implies 
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term&coefficient&value\\
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term&coefficient&value\\
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1&&(3a)^8(+4b)^0\\
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and from there, you can simplify the elements of the expansion by combining the coefficients

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Question

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