Answer:
The answer is
<h2>203.60 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of lead = 550 g
density = 2.70 g/mL
It's volume is
We have the final answer as
<h3>203.60 mL</h3>
Hope this helps you
This problem is asking for the intermolecular forces in ethanamine, C₂H₅NH₂. Hence, after analyzing it, we find they are both London dispersion forces and hydrogen bonding.
<h3>Intermolecular forces</h3>
In chemistry, intermolecular forces are the responsible of holding molecules together both in liquids and solids, and they depend on the type of bonds exhibited by the molecule. In this case, ethanamine:
Has C-C, C-H, C-N and N-H bonds. Now, C-C, C-H and N-H are strongly nonpolar as they have an electronegativity difference below 0.7, which means ethanamine has London dispersion forces as the weakest ones.
In addition, the presence of N-H bonds, provides this molecule with stronger intermolecular forces, hydrogen bonding, which occur in N-H and O-H bonds.
Learn more about intermolecular forces: brainly.com/question/17111432
Answer:
Net ionic equation:
H⁺(aq) + OH⁻(aq) → H₂O(l)
Explanation:
Balanced Chemical equation:
HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)
Ionic equation:
H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)
Net ionic equation:
H⁺(aq) + OH⁻(aq) → H₂O(l)
The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation. The water can not be splitted into ions because it is present in liquid form.
Spectator ions:
These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
(1) Protons have a positive charge, so will be repelled by other positive charges
(2) Neutrons have no charge, so won't be affected by positive charges
(3) Electrons have a negative charge, so will be attracted by a positive charge
(4) Positrons have a positive charge, so will be repelled by other positive charges
The answer is (3)
Answer:
Rate = 43 M⁻¹s⁻¹[NO₂][O₃]
Explanation:
We need to find the reaction order in
rate = (NO₂ )ᵃ (O₃ )ᵇ
given:
( NO₂ ) M ( O₃ ) M Rate M/s
0.10 0.33 1.420 (1)
0.10 0.66 2.840 (2)
0.25 0.66 7.10 (3)
When keeping the NO₂ concentration constant in the first two while doubling the concentration of O₃ , the rate doubles. Therefore it is first order with respect to O₃
Comparing (2) and (3) increasing the concentration of NO₂ by a factor of 2.5 and keeping O₃ constant , increased the rate by a factor of 2.5. Therefore the rate is first order with respect to NO₂
Then rate law is
= k (NO₂) (O₃ )
To find k take any of the three and substitute the values to find k:
1.420 M/s = k (0.10)M x (0.33)M ⇒ k = 43 /Ms
Then the answer is Rate = 43 M⁻¹s⁻¹[NO₂][O₃]