Answer:
The chance that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses is P=0.0488.
Step-by-step explanation:
To solve this problem we divide the tossing in two: the first 5 tosses and the last 5 tosses.
Both heads and tails have an individual probability p=0.5.
Then, both group of five tosses have the same binomial distribution: n=5, p=0.5.
The probability that k heads are in the sample is:

Then, the probability that exactly 2 heads are among the first five tosses can be calculated as:

For the last five tosses, the probability that are exactly 4 heads is:

Then, the probability that there will be exactly 2 heads among the first five tosses and exactly 4 heads among the last 5 tosses can be calculated multypling the probabilities of these two independent events:

The reason is the gotter of the right angle is 12
If we know that two sets of corresponding angles and the corresponding included sides are congruent in two triangles, what can we say about the triangles?
Answer: 6 minutes.
Step-by-step explanation: You can use a graphing calculator to see the exact graph, but you're trying to figure out what value of x gives you a y of 0. -50 times 6 is 300, plus 300 equals 0.
5m-n
Just replace m with 4 and n with 9
5(4)-9=20-9=11