<span>Your answer is -0.5 hope it helps:)
Also, I changed my pfp so know it's not team 10 no more</span>
Have you found the answer?
Step 1: Simplify both sides of the equation.
Step 2: Subtract 6x from both sides.
- 65x²+390x+585−6x=6x−6x
- 65x²+384x+585=0
For this equation: a=65, b=384, c=585
Step 3: Use quadratic formula with a=65, b=384, c=585
- x=−b±√b2−4ac/2a
- x=−(384)±√(384)2−4(65)(585)/
- 2(65)
- x=−384±√−4644/130
Therefore, There are no real solutions.
Answer:
2.44
Step-by-step explanation:
Given: x³ + 2x² - 5ax - 7 and x³ + ax² - 12x + 6
Also, R1 + R2 = 6
in order to find the value of a:
Let p(x) = x³ + 2x² - 5ax - 7 and q(x) = x³ + ax² - 12x + 6
Using remainder theorem i.e if a polynomial p(x) is divisible by polynomial of form x - a then remainder is given by p(a).
Then,
R1 = p( -1 ) = (-1)³ + 2(-1)² - 5a(-1) - 7 = -1 + 2 + 5a - 7 = 5a - 6
R2 = q( 2 ) = 2³ + a(2)² - 12(2) + 6 = 8 + 4a - 24 + 6 = 4a - 10
Now,
R1 + R2 = 6
5a - 6 + 4a - 10 = 6
9a = 22
a=2.44
Therefore, Value of a is 2.44
