All categories

3 years ago

What is the value of x in the equation 3x – 1/9 = 18, when y = 27?

Mathematics

2 answers:

Molodets [167]3 years ago

8 0

Answer:

Here you go mate!

Step-by-step explanation:

gogolik [260]3 years ago

3 0

Answer:

x = 7

Step-by-step explanation:

3x - 1/9y = 18

Put y as 27 and evaluate.

3x - 27/9 = 18

3x - 3 = 18

Add 3 on both sides.

3x = 21

Divide 3 on both sides.

x = 7

You might be interested in

1.) A. Graph A

vodka [1.7K]

Answers:

1) To emphasize the slow increase in profits, it would be best for Bradley to use <u>Graph A</u> for his presentation.

2) Bradley should use this graph for his presentation becauase the profit <u>appears to increase less</u> on this graph.

6 0

3 years ago

Read 2 more answers

Approximately how fast does a car have to travel if it can travel from North Carolina to New York in 12 hours

garri49 [273]

The distance is approximately 703 kilometers.
To travel that in 12 hours, a car has to go at 703/12=58.583 km/h

3 0

3 years ago

Kimberly Burns 360 cal in 45 minutes while jogging determine how many calories can really burns per minute

IgorLugansk [536]

Answer:

Step-by-step explanation:

360 divided by 45 is 8 calories per minute

8 0

3 years ago

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

3 years ago

Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used

ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes head start

Senn needs to give Ms. Beetle 18.4 minutes head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0

3 years ago