-v6,-23,2,2.5
Correct to ascending order
ABCDEDJGHIKLMNOP
sorry just wanted to see if the bold thing works
Answer:
<u>Diagram 1</u>
Draw a circle with a radius of 8 cm, ensuring you have clearly marked the center point (black circle with center C1)
Add a point on the circumference of the circle (point C2)
Draw a second circle of radius 8cm with point C2 as its center (red circle with center C2).
<u>Diagram 2</u>
The red circle intersects the black circle at two points (D and E).
Connect these 2 points of intersection with a line segment.
<u>Diagram 3</u>
Draw a third circle with center D and radius DE (shown in blue)
This circle intersects the black circle at point F.
<u>Diagram 4</u>
Draw 2 line segments to connect points D and E with point F - this is your equilateral triangle inside the circle!
The correct answer for this statement would be TRUE. Yes,it is true that the identity function is a linear function. <span>A linear function is a map between two vector spaces that preserves vector addition and scalar multiplication.
</span>this means f(x + y) = f(x) + f(y) and f(xy) = f(x)f(y))
<span>The identity function is the function such that f(x) = x
</span>So by using this example, we can conclude that it is a linear function.