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Tju [1.3M]
4 years ago
12

Jimmy's costume requires ⅞ + ½ + 1 3/4 yards of fabric. His sister's costume requires 3 x (⅞ + ½ + 1 ⅔) the amount of fabric tha

t Jimmy needs. What is the relationship between how much fabric Jimmy needs and how much fabric his sister needs?
Mathematics
1 answer:
liq [111]4 years ago
7 0

Answer:

The correct answer is fabric Jimmy's sister needs = \frac{73}{8} × fabric Jimmy needs = \frac{73}{8} × \frac{25}{8} yards of fabric.

Step-by-step explanation:

Jimmy's costume requires ⅞ + ½ + 1 \frac{3}{4} yards of fabric = \frac{7}{8} +\frac{4}{8} + \frac{14}{8} = \frac{25}{8} yards.

His sister's costume requires 3 x (⅞ + ½ + 1 ⅔) the amount of fabric that Jimmy needs = 3× (\frac{21}{24} + \frac{12}{24} + \frac{40}{24} ) yards of what Jimmy needs = \frac{73}{8} yards of what Jimmy needs.

The relationship between how much fabric Jimmy needs and how much fabric his sister needs is given by

Fabric Jimmy's sister needs = \frac{73}{8} × fabric Jimmy needs = \frac{73}{8} × \frac{25}{8} yards of fabric.

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If abc avw find the values of x and y
zavuch27 [327]

Answer:

x=7.2 y=7.5 this is the answer

8 0
3 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

8 0
3 years ago
The product of two ratio rational numbers is 48/5. If one of the rational number is 66/7, find the other rational number.
goldenfox [79]
Let x = the other rational number.

x(66/7) = (48/5)

Solve for x to find your answer.
3 0
3 years ago
Which is perpendicular to the line y=-3x-8y
atroni [7]

Answer:

I believe the answer is y = -7/3x

Step-by-step explanation:

When you rearrange the equation, y = -3x - 8y, you will get -7y = -3x.

We want the equation to be equal to y by itself. So we divide -7 from both sides, giving us the equation y = 3/7x.

The graph that is perpendicular to y = 3/7x is it's reciprocal: y = -7/3x

4 0
3 years ago
Read 2 more answers
Please help with this
Blizzard [7]

The probability is 4:20

It is correct because there are 20 students and there could be 4 guesses

5 0
3 years ago
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