Ask question

Ask question

All categories

4 years ago

13

What is the rational number equivalent to 3 point 24 with a bar over 24? (1 point) 3 and 6 over 97 3 and 28 over 99 3 and 8 over

33 3 and 10 over 32

2 answers:

dezoksy [38]4 years ago

7 0

Answer:

3 8/33

Step-by-step explanation:

i hope this helps

Olenka [21]4 years ago

4 0

3.24 (24 repeating)

= 3 8/33 because (8/33 = 0.24 --->24 repeating)

Hope it helps.

You might be interested in

15 divided by 22.8.

JulijaS [17]

.6578 this would be the answer

6 0

3 years ago

p Mes mm place .5 35 yards long She needs to cut frees 3 in it s we greatest number of pieces that she can ea A

bonufazy [111]

She will have aprox. 40 pieces of ribbon

5 0

3 years ago

an airplane travels 4688 kilometers against the wind in 8 hours and 5808 kilometers with the wind in the same amount of time. wh

Vladimir [108]

The speed of wind is 656 kmph and speed of plane is 70 kmph.

<u>SOLUTION: </u>

Given that, an air-plane travels 4688 kilometers against the wind in 8 hours

And 5808 kilometers with the wind in the same amount of time.

We have to find the rate of the plane in still air and the rate of wind

Now, let the speed of wind be a kmph and speed of plane be b kmph.

And we know that, $\text { distance }=\text { speed } \times \text { time }$

$\begin{array}{l}{\text { Then, while travelling with wind } \rightarrow 5808=(a+b) \times 8 \rightarrow a+b=726 \rightarrow a=726-b \rightarrow(1)} \\\\ {\text { While travelling against wind } \rightarrow 4688=(a-b) \times 8 \rightarrow a-b=586 \rightarrow(2)}\end{array}$

Substituting (1) in (2) we get,

$\Rightarrow 726-b-b = 586\Rightarrow -2b=586-726 \Rightarrow -2b=-140$

$\Rightarrow b=\frac{140}{2} \Rightarrowb=70\Rightarrow (3)$

On substituting (3) in (1) we get,

$a=726-70=656\Rightarrow a=656$

Hence, the speed of wind is 656 kmph and speed of plane is 70 kmph.

4 0

4 years ago

Can the ratio 75 to 90 be simplified? If so, what is the simplified ratio?

Alina [70]

75:90
15:18
5:6 is the simplified of 75:90

6 0

3 years ago

Please help me with that

PtichkaEL [24]

Common solution for each problem:
let
1st point=(x1,y1)
&,
2nd point=(x2,y2),then,

distance between 1st and 2nd point is:
√[(x2-x1)²+(y2-y1)²]

Just replace these x2,y2,x1,y1 with given points and you will get required answer..

7 0

3 years ago