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eimsori [14]
3 years ago
13

What is the rational number equivalent to 3 point 24 with a bar over 24? (1 point) 3 and 6 over 97 3 and 28 over 99 3 and 8 over

33 3 and 10 over 32
Mathematics
2 answers:
dezoksy [38]3 years ago
7 0

Answer:

3 8/33

Step-by-step explanation:

i hope this helps

Olenka [21]3 years ago
4 0

3.24 (24 repeating)

= 3 8/33 because (8/33 = 0.24 --->24 repeating)

Hope it helps.

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Find the perimeter of WXYZ. Round to the nearest tenth if necessary.
yanalaym [24]

Answer:

C. 15.6

Step-by-step explanation:

Perimeter of WXYZ = WX + XY + YZ + ZW

Use the distance formula, d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} to calculate the length of each segment.

✔️Distance between W(-1, 1) and X(1, 2):

Let,

W(-1, 1) = (x_1, y_1)

X(1, 2) = (x_2, y_2)

Plug in the values

WX = \sqrt{(1 - (-1))^2 + (2 - 1)^2}

WX = \sqrt{(2)^2 + (1)^2}

WX = \sqrt{4 + 1}

WX = \sqrt{5}

WX = 2.24

✔️Distance between X(1, 2) and Y(2, -4)

Let,

X(1, 2) = (x_1, y_1)

Y(2, -4) = (x_2, y_2)

Plug in the values

XY = \sqrt{(2 - 1)^2 + (-4 - 2)^2}

XY = \sqrt{(1)^2 + (-6)^2}

XY = \sqrt{1 + 36}

XY = \sqrt{37}

XY = 6.08

✔️Distance between Y(2, -4) and Z(-2, -1)

Let,

Y(2, -4) = (x_1, y_1)

Z(-2, -1) = (x_2, y_2)

Plug in the values

YZ = \sqrt{(-2 - 2)^2 + (-1 -(-4))^2}

YZ = \sqrt{(-4)^2 + (3)^2}

YZ = \sqrt{16 + 9}

YZ = \sqrt{25}

YZ = 5

✔️Distance between Z(-2, -1) and W(-1, 1)

Let,

Z(-2, -1) = (x_1, y_1)

W(-1, 1) = (x_2, y_2)

Plug in the values

ZW = \sqrt{(-1 -(-2))^2 + (1 - (-1))^2}

ZW = \sqrt{(1)^2 + (2)^2}

ZW = \sqrt{1 + 4}

ZW = \sqrt{5}

ZW = 2.24

✅Perimeter = 2.24 + 6.08 + 5 + 2.24 = 15.56

≈ 15.6

5 0
3 years ago
Tom's weight = 500 pounds
ruslelena [56]

Answer:

88% of his weight remains

5 0
2 years ago
How can i determine the sale price if you were given the regular price and percent of markdown
algol [13]
You would multiply the sales regular price by the percent and then subtract your answer from the regular sale price. For example, if something cost $499 and the sales price was 15% off, you would multiply 499 by 0.15 and then you would get 74.85.
7 0
3 years ago
Read 2 more answers
The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d
KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                     = \sqrt{(1-4)^2+(-5+3)^2}

                     = \sqrt{(-3)^2+(-2)^2}

                     = \sqrt{13}

Distance BC = \sqrt{(4-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance CD = \sqrt{(-2-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance AD = \sqrt{(1+2)^2+(-5+3)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Slope of AB (m_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                           = \frac{4-1}{-3+5}

                           = \frac{3}{2}

Slope of BC (m_{2}) = \frac{4-1}{-3+1}

                            = -\frac{3}{2}

If AB and BC are perpendicular then,

m_{1}\times m_{2}=-1

But it's not true.

[m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2}) = -\frac{9}{4}]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \frac{4+2}{-3+3}

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \frac{1-1}{-1+5}

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0
3 years ago
En un 9no grado, la asignatura de matemáticas la han aprobado el 62.5% de las alumnas y el 80% de los alumnos, mientras que la a
Paha777 [63]

Answer:

In the classroom there are 16 girls and 20 boys

Step-by-step explanation:

The question in English is

In the ninth grade, 62.5% of girls and 80% of boys passed the mathematics course, while 87.5% of girls and 60% of boys passed the history course. Calculate the number of students in the classroom, if the total number of passes is 26 in both subjects

Let

x ----> total girls in the classroom

y ---> total boys in the classroom

we know that

mathematics course

0.625x+0.80y=26 -----> equation A

history course

0.875x+0.60y=26 ----> equation B

Solve the system of equations by graphing

Remember that the solution is the intersection point both graphs

using a graphing tool

The solution is the point (16,20)

see the attached figure

therefore

In the classroom there are 16 girls and 20 boys

3 0
3 years ago
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