Answer:0.001
x=the number of workers taking the bus to work
p= probability of success =(15/100) = 0.15
q= probability of failure =1- p = 0.85
P(X=6) = 10C6(0.15)^6(0.85)^4
             = 0.001
 
        
                    
             
        
        
        
15 goes into 18 once with 3 remainder.
18/15-15/15=3/15=1/5
So the answer is:
 
 
        
        
        

The rows add up to 

, respectively. (Notice they're all powers of 2)
The sum of the numbers in row 

 is 

.
The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When 

,

so the base case holds. Assume the claim holds for 

, so that

Use this to show that it holds for 

.



Notice that






So you can write the expansion for 

 as

and since 

, you have

and so the claim holds for 

, thus proving the claim overall that

Setting 

 gives

which agrees with the result obtained for part (c).
 
        
             
        
        
        
Answer:
V = −1
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
3=−2v−v
3=−2v+−v
3=(−2v+−v)(Combine Like Terms)
3=−3v
3=−3v
Step 2: Flip the equation.
−3v=3
Step 3: Divide both sides by -3.
<u>−3v</u>  = <u>3</u>
 -3     -3
v=−1