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vekshin1
3 years ago
7

1b. $1 6​− 1 3​ Lin said the value of this expression is $ 1 6​. Is she correct? Explain or show your reasoning to prove your an

swer
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

No she is not correct

Step-by-step explanation:

She is not correct because “value of expressions” mean the result which for this it is 16-13 =3 and she is wrong. please mark me brainly! Hope this helps! :D

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Please help me I tried to do it
anyanavicka [17]
You do 9x27=243 then take 2x31=62 add 243+62=305 then take 305 and subtract it from 28 305-28=277 
so if i did it right you should get n=277
8 0
3 years ago
Susan is writing a linear equation for the cost of her cell phone plan. In the first month, she talks for 52 minutes and is char
Alex787 [66]
Assuming that the cost per minute is the same for both months and the plan fee is the same, you can use y=mx+b for this

y is the cost of the phone plan, x is the cost per minute and b is the start cost.

so    19.41=25x+b for the first month
and  45.65=380x+b for the second month

solve both for b you get:
19.41-25x=b and 45.65-380x=b.  from this we get
19.41-25x=45.65-380x

solve for x

328x=26.24 and x=0.08

this means the cost per minute is 0.08c/min (answer A)

rewrite the equation to calculate b, and where this time, the x is the number of minutes talked.

y=0.08x+b and plug in one of the two months

45.65=0.08 * 380 + b

Solve for b and b is 15.25

so the final equation is

y=0.08x+15.25  (answer B)
5 0
3 years ago
On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi
Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0
3 years ago
Find the value of the variable.
Vedmedyk [2.9K]

Answer:

boom ganag

Step-by-step explanation:

5 0
2 years ago
2.50+ 1.50(m-1)=17.50
neonofarm [45]

Answer: m = 11

Step-by-step explanation: Isolate the variable by dividing each side by facotrs that don't contain the variable.

Hope this helps you out! ☺

4 0
3 years ago
Read 2 more answers
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