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Lana71 [14]
3 years ago
5

What is the range of the data shown on the stem-and-leaf plot?

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

50

Step-by-step explanation:

the given data is

93     43     50     48

the range is given by the following formula :

Range = Vmax - Vmin

where

Vmax= maximum value of Data

Vmin= minimum value of Data

from the given data ,

Vmax  = 93 and Vmin = 43

hence,

Range = 93 - 43

Range = 50

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I can’t figure out the surface area. Someone please help !! :)
Ilia_Sergeevich [38]
<h3> Answer:</h3><h2>surface area is 227•1</h2><h2>volume is 321•7</h2>

Step-by-step explanation:

diameter is 8•5

radius is d/2

8•5/2

=4•25

surface area = 4πr^2

4×22/7×4•25×4•25

=1589•5/7

=227•1

Volume= 4/3πr^3

4/3×22/7×4•25×4•25×4•25

4/3×22/7×76•76

=321•7

Hope it helps

plz mark as brainliest

5 0
3 years ago
Solve the formula V=h for r.
AnnyKZ [126]

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

2

cos

(

x

)

−

1

=

0

3

x

=

4

−

x

x

−

5

=

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3

Step-by-step explanation:

5 0
3 years ago
bacteria colonies can triple in size every 4 days. If you start with 150 bacteria microorganisms, how large with the colony be a
-Dominant- [34]
It triples in size every 4 days.  In 16 days it will be 3 * 3 * 3 * 3 times bigger.

3 * 3 * 3 * 3 = 81
Therefore, after 16 days, the colony will contain (81 * 150) or 12,150 microorganisms.


6 0
3 years ago
Alex has x number of baseball cards Danny has 10 more baseball cards than Alex how many baseball cards does Danny have:write you
Vilka [71]

Answer:

x+10

Danny has 10 + x baseball cards

7 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
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