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Combine like terms

Add 1 and subtract 6x from each side
0 = 12
The equation has no real solution
Answer:
Lower (or First) Quartile = 15
Step-by-step explanation:
Answer:
Step-by-step explanation:
Multiply each term of the first polynomial with the second polynomial. Then combine the like terms.
(3a<em>² + 5a - 2)* (5a² -3a + 4)</em>
<em> = 3a² *(5a² -3a + 4) + 5a*(5a² -3a + 4) - 2*(5a² -3a + 4)</em>
<em>=3a²*5a² - 3a*3a² + 4*3a² + 5a*5a² - 3a*5a + 4*5a + 5a²*(-2) - 3a*(-2) + 4*(-2)</em>
<em>=15a⁴ - 9a³ + 12a² + 25a³ - 15a² + 20a - 10a² + 6a - 8</em>
<em>= 15a⁴ </em><u><em>- 9a³ + 25a³</em></u><em> +</em><u><em> 12a² - 15a² - 10a²</em></u><em> +</em><u><em> 20a +6a </em></u><em>- 8</em>
<em>= 15a⁴ + 16a³ - 13a² +26a - 8</em>
Answer:
The equation of the line is y =
x + 2
Step-by-step explanation:
The form of the equation that passes through two points (x1, y1) and (x2, y2) is y = m x + b, where
- m is the slope of the line whose rule is
- b is the y-intercept, you can find it by substituting x, y in the equation by (x1, y1) OR (x2, y2)
Let us solve the question:
∵ The line passes through the points (-3, -2) and (3, 6)
∴ x1 = -3 and x2 = 3
∴ y1 = -2 and y2 = 6
→ Use the rule of m to find it
∵ 
→ Simplify it by dividing up and down by 2
∴ m = 
→ Substitute its value in the form of the equation above
∴ y =
x + b
→ To find b substitute x and y by x1 and y1
∴ -2 =
(-3) + b
∴ -2 = -4 + b
→ Add 4 to both sides
∴ -2 + 4 = -4 + 4 + b
∴ 2 = b
→ Substitute it in the form of the equation
∴ y =
x + 2
∴ The equation of the line is y =
x + 2