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ivanzaharov [21]
3 years ago
11

​f(x)=5​x reflected over the x axis

Mathematics
1 answer:
postnew [5]3 years ago
6 0

Answer:

f(x) = -5x

Step-by-step explanation:

Just add a - sign to reflect it over the x axis

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-3x+4=16<br> PLEASE SOLVE THIS!!
postnew [5]


-3X+4=16

Subtract 4 from each side.

-3x+4-4=16-4

-3x=12

Divide each side by -3.

x=-4

I hope this helps!

6 0
3 years ago
Read 2 more answers
Solve for x 2/5 x = 6/5 <br><br> answer choices<br><br> 12/15<br><br> 12/5<br><br> 3<br><br> 6
SIZIF [17.4K]
The answer is 3. 
<span><span>65</span>÷<span>25</span></span><span>=
<span>(6 × 5) (5 × 2)</span></span><span>=<span>30
10</span></span><span>=<span>30 ÷ 10
10 ÷ 10</span></span><span>=<span>3</span></span>
5 0
3 years ago
The least common multiple of two numbers is 40. The difference of the two numbers is 2. What are the numbers?
Olin [163]
8 and 10 because 8 x 5 equals 40 and 10 x 4 equals 40. and 10 minus 8 is two
4 0
3 years ago
If y varies inversely as x and y = 40 when x = 5, then the constant is
exis [7]
The answer is b. 200

<span>If y varies inversely as x, then: y = c/x

We know:
y = 40
x = 5

y = c/x
c = y * x
c = 40 * 5
c = 200</span>
8 0
3 years ago
Read 2 more answers
Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0
3 years ago
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