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alukav5142 [94]
3 years ago
14

Factor by using the perfect-square trinomial formula. 100x^2+20x+1

Mathematics
2 answers:
a_sh-v [17]3 years ago
8 0
To factor first multily 100 and 1 and get 100

then find what 2 numbers multiply to get 100 and add to get 20

the numbers are 10 and 10

so
split the center term up
100x^2+10x+10x+1
group
(100x^2+10x)+(10x+1)
undistribute
(10x)(10x+1)+(1)(10x+1)
undistribute/reverse distributive property
(10x+1)(10x+1)
(10x+1)^2
Ratling [72]3 years ago
6 0
<span>since this is a perfect square problem, the answer will be in the form (ax + b) ^ 2. what can you tell from looking at the original equation? x^2 does not have a coefficient in front of it, so a = 1. the second term is negative, so b must be negative. finally, the last number 100 is the square of + or - 10, so b must be +10 or -10, but we already figured b has to be negative, so b = -10
</span>
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Given the function f(x) = 3x, find the value of f−1(27). f−1(27) = 1 f−1(27) = 3 f−1(27) = 9 f−1(27) = 81
Mariulka [41]
Fun fact
if f(a)=b then f⁻¹(b)=a
so
if f⁻¹(b)=a then f(a)=b
 
so we find f(x)=27 and the solve for x

f(x)=3x=27
3x=27
divide both sides by 3
x=9

so if f(9)=27 then f⁻¹(27)=9
problem solved

answer is 9
7 0
3 years ago
What is x/9 = 9/27 help plz
Irina18 [472]
<h3><u>QUES</u><u>TION</u><u>:</u><u> </u></h3>

what is x/9 = 9/27 help plz

<h3><u>ANSWER</u><u> </u><u>AND</u><u> </u><u>SOLU</u><u>TION</u><u>:</u><u> </u></h3>

  • SOLVING FOR X

<u>Reduce</u><u> </u><u>first</u><u> </u><u>the</u><u> </u><u>fraction</u><u> </u><u>with</u><u> </u><u>9</u>

\large \sf  = \dfrac{x}{9}  =  \dfrac{ \cancel9}{ \cancel{27}}

<u>\large \sf =  \dfrac{x}{9}  =  \dfrac{1}{3}</u>

<u>Now</u><u> </u><u>simpli</u><u>fy</u><u> </u><u>using</u><u> </u><u>cross-multiply</u>

<u>\large \sf  = \dfrac{3x}{9}  = 1</u>

<u>\large \sf = 3x = 1 \times 9</u>

<u>\large \sf = 3x = 9</u>

<u>Lastly</u><u> </u><u>divide</u><u> </u><u>both</u><u> </u><u>sides</u>

<u>\large \sf = 3x \div 3 = 9 \div 3</u>

<u>\large \sf = x = 9  \div 3</u>

<u>\large \sf = x = 3</u>

<h3><u>FINAL</u><u> </u><u>ANSWER</u><u>:</u></h3>

\huge \orange{ \underline{ \boxed{ \sf{x = 3}}}}

HOPE THIS HELP YOU! HAVE A NICE DAY!

~kimtaetae92~

7 0
3 years ago
Check image giving brainliest to first correct answer
Snowcat [4.5K]

Answer:

<em>7</em>

Step-by-step explanation:

<em>S</em><em>o</em><em>:</em><em>a</em><em>=</em><em>3</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>b</em><em>=</em><em>(</em><em>-</em><em>2</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>c</em><em>=</em><em>2</em>

<em>S</em><em>u</em><em>b</em><em>s</em><em>t</em><em>i</em><em>t</em><em>u</em><em>t</em><em>e</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>n</em><em>u</em><em>m</em><em>b</em><em>e</em><em>r</em><em>s</em><em> </em><em>i</em><em>n</em><em>t</em><em>o</em><em> </em><em>e</em><em>a</em><em>c</em><em>h</em><em> </em><em>letters</em>

<em> </em><em>s</em><em>o</em><em> </em><em>a</em><em> </em><em>i</em><em>s</em><em> </em><em>r</em><em>e</em><em>p</em><em>r</em><em>e</em><em>s</em><em>e</em><em>n</em><em>t</em><em>e</em><em>d</em><em> </em><em>b</em><em>y</em><em> </em><em>3</em><em>,</em><em>c</em><em> </em><em>b</em><em>y</em><em> </em><em>2</em><em> </em><em>a</em><em>n</em><em>d</em><em> </em><em>b</em><em> </em><em>-</em><em>2</em>

<em> </em><em>t</em><em>h</em><em>e</em><em>r</em><em>e</em><em>f</em><em>o</em><em>r</em><em>e</em><em> </em><em>g</em><em>i</em><em>v</em><em>i</em><em>n</em><em>g</em><em> </em><em>u</em><em>s</em><em>:</em><em> </em><em> </em><em> </em><em> </em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>+</em><em>(</em><em>-</em><em>2</em><em>)</em><em>=</em><em>9</em><em>+</em><em>(</em><em>-</em><em>2</em><em>)</em><em>=</em><em>7</em>

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