the complete question is
Find two numbers whose difference is 46 and whose product is a minimum
Let
x------->larger number
y-------> smaller number
P-------> product of the two numbers
we know that
-----> equation 1
-----> equation 2
substitute equation 1 in equation 2
![P=x*[x-46]\\ P=x^{2} -46x](https://tex.z-dn.net/?f=%20P%3Dx%2A%5Bx-46%5D%5C%5C%20P%3Dx%5E%7B2%7D%20-46x%20)
using a graph tool
see the attached figure
Find the value of x for that the product P is a minimum
the vertex is the point 
that means, for 
the product is a minimum 
find the value of y

therefore
the answer is
the numbers are
and 
Answer:
a is <u>5</u><u>3</u><u>.</u><u>8</u><u>°</u><u>,</u> and b is <u>3</u><u>6</u><u>.</u><u>2</u><u>°</u>
Step-by-step explanation:
Using sine trig rule:


Summation of angles of triangle:

Answer:
Option A
Step-by-step explanation:
since V = p×r^2×h
r = 3/2
hence, option a is correct.
The answer I believe would be 7
Answer:
C
Step-by-step explanation:
A cube has 6 square faces
Each face: 5² = 25
Surface area: 6(25) = 150 in²