Answer:
The question = (7^3)*(7^x)
When multiplying two exponents with the same base, all you do is add the exponents together and keep the same base
Therefore,
(7^3)*(7^x) = 7^(3+x)
Step-by-step explanation:
7^3+x is the answer
Step-by-step explanation:
Putting values of x and y
2 = 4 + 2
2 = 6
= 6-2
= 4
Answer:
![15.75x^{10}y^{19}](https://tex.z-dn.net/?f=15.75x%5E%7B10%7Dy%5E%7B19%7D)
Step-by-step explanation:
To find the 5th term in the expansion, we first will need to apply the binomial theorem. I have attached an image of the binomial theorem formula due to not being able to type it.
After applying the binomial theorem and simplifying, you should get:
![512x^{18}y^{27}-576x^{16}y^{25}+288x^{14}y^{23}-84x^{12}y^{21}+\frac{63x^{10}y^{19}}{4}-\frac{63x^8y^{17}}{32}+\frac{21x^6y^{15}}{128}-\frac{9x^4y^{13}}{1024}+\frac{9x^2y^{11}}{32768}-\frac{y^9}{262144}](https://tex.z-dn.net/?f=512x%5E%7B18%7Dy%5E%7B27%7D-576x%5E%7B16%7Dy%5E%7B25%7D%2B288x%5E%7B14%7Dy%5E%7B23%7D-84x%5E%7B12%7Dy%5E%7B21%7D%2B%5Cfrac%7B63x%5E%7B10%7Dy%5E%7B19%7D%7D%7B4%7D-%5Cfrac%7B63x%5E8y%5E%7B17%7D%7D%7B32%7D%2B%5Cfrac%7B21x%5E6y%5E%7B15%7D%7D%7B128%7D-%5Cfrac%7B9x%5E4y%5E%7B13%7D%7D%7B1024%7D%2B%5Cfrac%7B9x%5E2y%5E%7B11%7D%7D%7B32768%7D-%5Cfrac%7By%5E9%7D%7B262144%7D)
Our 5th term here is:
which is equal to ![15.75x^{10}y^{19}](https://tex.z-dn.net/?f=15.75x%5E%7B10%7Dy%5E%7B19%7D)
~Hope this helps! Sorry if my answer is confusing at all, it's pretty difficult to explain.~
Step-by-step explanation:
From the figure it is clear that:
x+110°=180
x=180-110
x=70
For y:
the left exterior angle of line q is also70.
By the definition of alternate exterior angle:
y=70
<u>Note</u><u>:</u><u>i</u><u>f</u><u> </u><u>you</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>a</u><u>s</u><u>k</u><u> </u><u>a</u><u>n</u><u>y</u><u> </u><u>question</u><u> </u><u>please</u><u> </u><u>let</u><u> </u><u>me</u><u> </u><u>know</u><u>.</u>
Start looking like the standards because y’all starting to look the same