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Brut [27]
3 years ago
11

Solve for y=4x-300 and y=3x+600

Mathematics
1 answer:
lara31 [8.8K]3 years ago
7 0
Subsitute 4x-300 for y
4x-300=3x+600
subtract 3x form both isdes
x-300=600
add 300 to both sides
x=900
subsitute 900 for x
y=4(900)-300
y=3600-300
y=3300

x=900
y=3300
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Answer: D
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Katie would be correct if she had lines within the L shaped area

5 0
3 years ago
The value of a dirt bike decreases by 15% each year. If you purchased this dirt bike today for $500, to the nearest dollar how m
enot [183]
The bike would be worth $125 5 years later.
8 0
3 years ago
Read 2 more answers
What is the expression in radical form?<br><br> (4x3y2)310
sertanlavr [38]

Given:

Consider the given expression is

(4x^3y^2)^{\frac{3}{10}}

To find:

The radical form of given expression.

Solution:

We have,

(4x^3y^2)^{\frac{3}{10}}=(2^2)^{\frac{3}{10}}(x^3)^{\frac{3}{10}}(y^2)^{\frac{3}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{6}{10}}(x)^{\frac{9}{10}}(y)^{\frac{6}{10}}

(4x^3y^2)^{\frac{3}{10}}=(2)^{\frac{3}{5}}(x)^{\frac{9}{10}}(y)^{\frac{3}{5}}

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{2^3}\sqrt[10]{x^9}\sqrt[5]{y^3}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

(4x^3y^2)^{\frac{3}{10}}=\sqrt[5]{8y^3}\sqrt[10]{x^9}       [\because x^{\frac{1}{n}}=\sqrt[n]{x}]

Therefore, the required radical form is \sqrt[5]{8y^3}\sqrt[10]{x^9}.

8 0
4 years ago
Please answer my question below<br> Will give you a brainliest?
VARVARA [1.3K]

Answer:

1: 3\sqrt2 - \sqrt14

2: \sqrt21 - 2\sqrt(7)

3: 4\sqrt3 - \sqrt15

4: 2\sqrt5 - \sqrt10

5: -3 + 3\sqrt5

I already gave you these answers man

Step-by-step explanation:

7 0
4 years ago
Please help and show your work
Aliun [14]
To find the answer,we can set an equation adding up all the angles:

a°+2a°+2a°+a°=360°
6a°=360°
a°= 360°/6
a = 60

Therefore,the answer is 60.

Hope it helps!
7 0
3 years ago
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