What is 5543×3445+211÷3??? Please help me due today!!! I will give 10 points or maybe 20pts

Pls help a girl out ;-;

Sveta_85 [38]

The order of locations from highest to lowest is Caspian sea, lammefjord, Trins Alexanderpolder, Fenland, Raczki

Explanation:

The order of the locations from highest to lowest can be determined using the values of meters below sea level.

From the data, the highest to lowest value can be written as

28 meters

8 meters

7 meters

4 meters

2 meters

Thus, from the data, the locations from highest to lowest can be written as

Caspian sea

Lammefjord

Trins Alexanderpolder

Fenland

Raczki

8 0

3 years ago

Find the inverse of 3y = 3x - 6. Write your answer in y = form with no spaces to increase the chance of auto grade working.

STALIN [3.7K]

Hope the shown work helps!

8 0

2 years ago

Read 2 more answers

Can anyone do these two<br> a)√3(√3-1)<br> b)√5(√10+√2)

gogolik [260]

A 1.267949192
b 10.23334547

7 0

3 years ago

Distributive property Explained 4(x+3)=4x+12

ankoles [38]

Answer:

Step-by-step explanation:

4(x+3)=4x+12

4x+12=4x+12

4 0

3 years ago

A certain brand of candies have a mean weight of 0.8616g and a standard deviation of 0.0518 based on the sample of a package con

torisob [31]

Answer:

a) The probability is 0.5557 = 55.57%.

b) The probability that a sample of 447 candies will have a mean of 0.8542g or greater is 0.9987 = 99.87%.

c) Yes, because there is a very large probability, of 99.87%, that the amount will be at least the one claimed on the label.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean weight of 0.8616g and a standard deviation of 0.0518

This means that $\mu = 0.8616, \sigma = 0.0518$

a) If 1 candy is reandomly selected, find the probability that it weights more than 0.8542g.

This is 1 subtracted by the pvalue of Z when X = 0.8542. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{0.8542 - 0.8616}{0.0518}$

$Z = -0.14$

$Z = -0.14$ has a pvalue of 0.4443

1 - 0.4443 = 0.5557

The probability is 0.5557 = 55.57%.

b) If 447 candies are reandomly selected find the probability that their mean weight is at least 0.8542 g.

Sample of 447 means that $n = 447, s = \frac{0.0518}{\sqrt{447}} = 0.00245$

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.8542 - 0.8616}{0.0245}$

$Z = -3.02$

$Z = -3.02$ has a pvalue of 0.0013

1 - 0.0013 = 0.9987

The probability that a sample of 447 candies will have a mean of 0.8542g or greater is 0.9987 = 99.87%.

c) Given these results does it seem that the candy company is providing consumers with the amount claimed on the label?

Yes, because there is a very large probability, of 99.87%, that the amount will be at least the one claimed on the label.

6 0

2 years ago