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3 years ago

NEED DONE ASAP 20 PTS!!!!!!

Mathematics

2 answers:

kirill [66]3 years ago

7 0

X(x-4)=7
2x-8=7
2x=15
x=15/2
x=7.5

x^2+2x+2=0
cannot be factored

gayaneshka [121]3 years ago

3 0

X23 yo mama do ya own work

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Two friends, Jamie and Devin, are working together at the Sparrowtown Cafe today. Jamie works every 2 days, and Devin works ever

makvit [3.9K]

Answer:

14 days

Step-by-step explanation:

let assume they both work on Monday (today)

devin works every 7 days,that is devin works every Monday.

jamie has to work for 14 days inorder to work with devin again

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2 years ago

The random variable X = the number of vehicles owned. Find the expected number of vehicles owned. Round answer to two decimal pl

Lelechka [254]

Answer:

The expected number of vehicles owned to two decimal places is: 1.85.

Step-by-step explanation:

The table to the question is attached.

$E(X) =$ ∑ $xp(x)$

Where:

E(X) = expected number of vehicles owned

∑ = Summation

x = number of vehicle owned

p(x) = probability of the vehicle owned

$E(X) = (0 * 0.1) + (1 * 0.35) + (2 * 0.25) + (3 * 0.2) + (4 * 0.1)\\E(X) = 0 + 0.35 + 0.50 + 0.60 + 0.4\\E(X) = 1.85$

The expected number of vehicles owned is 1.85.

4 0

3 years ago

at fish world,clownfish are on sale for $5 off with a maximum of 6 fish per customer. Rudy buys 6 clownfish on sale plus 3 more

ICE Princess25 [194]

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3 years ago

Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.

loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>

$x^ax^b = x^{(a+b)}$
$\dfrac{x^a}{x^b} = x^{(a-b)}$
$(a^a)^b =x^{(a\times b)}$
$(xy)^a = x^ay^a$

$x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4$

The solution of the expression is $\dfrac{4x^4}{y^6}$ .

<h2>Explanation</h2>

Given to us

$(16x^8y^{12})^{\frac{1}{2}}$

Solution

We know that 16 can be reduced to $2^4$ ,

$=(2^4x^8y^{12})^{\frac{1}{2}}$

Using identity $(xy)^a = x^ay^a$ ,

$=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}$

Using identity $(a^a)^b =x^{(a\times b)}$ ,

$=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})$

Solving further

$=2^2x^4y^{-6}$

Using identity $\dfrac{x^a}{x^b} = x^{(a-b)}$ ,

$=\dfrac{2^2x^4}{y^6}$

$=\dfrac{4x^4}{y^6}$

Hence, the solution of the expression is $\dfrac{4x^4}{y^6}$ .

Learn more about Exponentiation:

brainly.com/question/2193820

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3 years ago