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AfilCa [17]
3 years ago
5

What is the set builder notation of A={1,8,27,64,125}

Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
A=\{1;\ 8;\ 27;\ 64;\ 125\}\\\\1^3=1\\2^3=8\\3^3=27\\4^3=64\\5^3=125\\\\Therefore,\ the\ set\ builder\ notation\ is:\\\boxed{A=\{y\in\mathbb{N}\ |\ y=x^3\ \wedge\ x\in\{1;\ 2;\ 3;\ 4;\ 5\}\}}
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A waitress sold 15 ribeye steak dinners and 18 grilled salmon​ dinners, totaling ​$559.81 on a particular day. Another day she s
Orlov [11]

Let  the steaks = X and the salmon = y.

Set up two equations:

15x + 18y = 559.81

19x + 9y = 583.66

Now using the elimination method:

Multiply the second equation by -2, then add the equations together.

(15x+18y=559.81)

−2(19x+9y=583.66)

Becomes:

15x+18y=559.81

−38x−18y=−1167.32

Add these equations to eliminate y:

−23x=−607.51

Divide both sides by -23 to solve for x:

x= -607.51 = -23 = 26.413478

Now you have the cost for a steak.

To solve for the cost of the salmon, replace x with the value in the first equation and solve for y.

15(26.413478) + 18y = 559.91

396.202174 + 18y = 559.81

Subtract 396.202174 from both sides:

18y = 163.607826

Divide both sides by 18:

y = 163.607826 / 18

y = 9.089324

Round both x and Y to the nearest cent:

X (Steaks) =$26.41

Y (Salmon) = $9.09

7 0
3 years ago
Help - sorry it’s blurry I couldn’t fix it
Natali5045456 [20]
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4 0
3 years ago
The regression equation for predicting number of speeding tickets (Y) from information about driver age (X) is Y = -.065(X) + 5.
ivolga24 [154]

Answer:

c. 4.27

Step-by-step explanation:

We have been given the regression equation of for predicting number of speeding tickets (Y) from information about driver age (X) as Y=-0.065(X)+5.57.

To find the predicted number of tickets for a twenty-year-old, we will substitute X=20 in our given equation.

Y=-0.065(20)+5.57

Y=-1.3+5.57

Y=4.27

Therefore, the predicted number of tickets for a twenty-year-old would be 4.27 tickets.

6 0
3 years ago
Which is more precise measurement? A:18 inches B:18.55 C:17.5 D: 17.775
Andrej [43]
17.775 is the most precise since it has the most decimals. However, it may not be correct.
4 0
3 years ago
Read 2 more answers
Three fair coins are tossed. If all land "heads," the player wins $10, and if exactly two land heads, the player wins $5. If it
hodyreva [135]

Answer:

<u>After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:</u>

<u>1/8 or 12.5% of landing three "heads"</u>

<u>3/8 or 37.5% of landing two "heads"</u>

<u>4/8 or 50% of landing no or only one "head".</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2.  What is the player's expected outcome after four games?

Probability of two coins out of three lands "heads" = 3/8

Probability of three coins out of three lands "heads" = 1/8

Now, let's calculate the player's expected outcome, as follows:

Four games:

Cost = 4 * 4 = $ 16

Worst-case scenario: No wins

Best-case scenario: 4 out of 4 of $ 10 win

Worst-case scenario profit or loss = 0 - 16 = Loss of $ 16

Best-case scenario profit or loss = 40 - 16 = Profit of $ 24

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

8 0
3 years ago
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