1. The probability that your mail is delivered before 2 pm is 0.9, so the probability that the mail is delivered at 2 pm or after 2 pm (so not before 2 pm) is 1-0.9=0.1.
Remark: 0.9=9/10=90/100=90%, and 0.1 is 10%
2. Probability of the mail being delivered before 2 pm for 2 consecutive days is
3. take a look at the picture attached, the tree diagram is another method we could use.
Answer:
Probability = 1/8.
Step-by-step explanation:
A number cube has six sides. Each side has a number from 1 to 6. This means that there are 3 even numbers (2, 4, and 6) and 3 odd numbers (1, 3, and 5). Therefore:
P(number cube lands on an even number after roll) = Number of even numbers/Number of total numbers. = 3/6 = 1/2.
Since the cube has to be rolled three times, the probability will be multiplied 3 times (assuming that each roll in independent of each other). Therefore:
P(number cube lands on an even number 3 times after roll) = 1/2 * 1/2 * 1/2 = 1/8.
Therefore, the answer is 1/8!!!
What’s da problem that u have?
Answer:
domain = all real numbers
Step-by-step explanation:
domain is the x axis
its asking what it goes to but if they have arrows then forever
Answer:
Option 2 is right
Step-by-step explanation:
Given that
We can write this in polar form with modulus and radius
Hence angle = 60 degrees and
Since we have got 5 roots for z, we can write 60, 420, 780, etc. with periods of 360
Using Demoivre theorem we get 5th root would be
5th root of 2 multiplied by 1/5 th of 60, 420, 780,....
![z= \sqrt[5]{2} (cos12+isin12)\\z=\sqrt[5]{2} (cos84+isin84)\\\\z=\sqrt[5]{2} (cos156+isin156)\\\\z=\sqrt[5]{2} (cos228+isin228)\\\\z=\sqrt[5]{2} (cos300+isin300)\\](https://tex.z-dn.net/?f=z%3D%20%5Csqrt%5B5%5D%7B2%7D%20%28cos12%2Bisin12%29%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos84%2Bisin84%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos156%2Bisin156%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos228%2Bisin228%29%5C%5C%5C%5Cz%3D%5Csqrt%5B5%5D%7B2%7D%20%28cos300%2Bisin300%29%5C%5C)
Out of these only 2nd option suits our answer
Hence answer is Option 2.
