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What is the complete cycle of ice wedging

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timofeeve [1]3 years ago

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Water works it way through a crack then it freezes

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Answer:

$\Delta S_u=2.1429\ J.K^{-1}$

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Explanation:

Given:

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temperature of sink reservoir, $T_L=350\ K$

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work done, $W=250\ J$

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Since heat engine is a device that absorbs heat from a high temperature reservoir and does some work giving out heat in the universe as the byproduct.

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$\Delta S_u=2.1429\ J.K^{-1}$

We know Carnot efficiency is given as:

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Now the Carnot work done:

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From eq. (1) we have the Carnot work, so the difference:

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