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d1i1m1o1n [39]
3 years ago
11

Which source of energy would you prefer for cooking and why?

Physics
1 answer:
timurjin [86]3 years ago
3 0

Answer:

gas

Explanation:

because It is fast and easy

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To practice Problem-Solving Strategy 25.1 Power and Energy in Circuits. A device for heating a cup of water in a car connects to
Rom4ik [11]

Answer:

It takes <u>951 seconds</u> to boil a cup of water.

Explanation:

Given:

EMF of the battery (E) = 10.0 V

Internal resistance of the battery (r) = 0.04 Ω

Resistance of the circuit = 'R'

Current measured in the circuit (I) = 11.0 A

Energy required to boil water (U) = 100 kJ = 100 × 10³ J [1 kJ = 10³ J]

Time taken for boiling (t) = ?

We know that, the emf of the battery is given as:

E=I(R+r)

Plug in the given values and solve for 'R'. This gives,

10=11(R+0.04)\\\\R+0.04=\frac{10}{11}\\\\R=\frac{10}{11}-0.04=0.909-0.04=0.869\ \Omega

Now, energy required to boil the water is given as:

U=I^2Rt

Plug in the given values and solve for 't'. This gives,

100\times 10^3\ J=(11.0\ A)^2(0.869\ \Omega)t\\\\t=\frac{100000\ J}{121\times 0.869\ A^2\Omega}\\\\t=\frac{100000\ J}{105.149\ A^2\Omega}\\\\t=951\ s

So, it takes 951 seconds to boil a cup of water.

5 0
3 years ago
5. An undisturbed soil sample has a wet density of 2.5 Mg/m3 when the water content is 25%. The specific gravity of the soil par
Dima020 [189]

Answer:

The submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

Explanation:

Given;

wet density of soil sample = 2.5 Mg/m³ = 25 kN/m³

Specific gravity of solid particle = 2.7

The dry unit weight of soil;

\gamma _d = \frac{\gamma _t}{1 +w} = \frac{25}{1+0.25} = 20 \ kN/m^3

for undisturbed state, the volume of the soil is;

V_s =\frac{\gamma _d}{G_s \gamma _w} = \frac{20}{2.7*9.81} = 0.76 \ m^3\\\\Void \ volume, V_v = 1-0.76 = 0.24 \ m^3

Void \ ratio, \ e = \frac{0.24}{0.76} = 0.32

Submerged effective density is given as;

\rho _b = \frac{\rho_w(\gamma_s -1)}{1+e}

density of water (ρw) = 2.7 x 25 kN/m³ = 67.5 kN/m³, substitute this in the above equation;

\rho _b = \frac{\rho_w(\gamma_s -1)}{1+e} =  \frac{67.5(2.7 -1)}{1+0.32} = 86.93 \ kN/m^3

Therefore, the submerged effective density is 86.93 kN/m³ or 8.693 Mg/m³

5 0
3 years ago
A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required
Ad libitum [116K]

Answer:

4N

Explanation:

a = (7-3)/5 = 0.8m/s^2

F = ma = (5)(0.8) = 4 Newtons

3 0
3 years ago
A source charge of 5.0 µC generates an electric field of 3.93 × 105 at the location of a test charge. How far is the test charge
kap26 [50]

Answer:

B. )  0.34 m

I definitely guessed and got the right answer so :))

6 0
3 years ago
Read 2 more answers
(pleases show work)
Feliz [49]

a. 46 m/s east

The jet here is moving with a uniform accelerated motion, so we can use the following suvat equation to find its velocity:

v=u+at

where

v is the velocity calculated at time t

u is the initial velocity

a is the acceleration

The jet in the problem has, taking east as positive direction:

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

Substituting t = 10 s, we find the final velocity of the jet:

v=16 + (3)(10)=46 m/s

And since the result is positive, the direction is east.

b. 310 m

The displacement of the jet can be found using another suvat equation

s=ut+\frac{1}{2}at^2

where

s is the displacement

u is the initial velocity

a is the acceleration

t is the time

For the jet in this problem,

u = +16 m/s  is the initial velocity

a=+3 m/s^2  is the acceleration

t = 10 s is the time

Substituting into the equation,

s=(16)(10)+\frac{1}{2}(3)(10)^2=310 m

4 0
3 years ago
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