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dybincka [34]
2 years ago
15

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti

on at A is μ = 0.4. Determine the magnitude of force at point and determine if the ladder will slip.
Physics
1 answer:
Colt1911 [192]2 years ago
5 0

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

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Answer:

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V = \frac{qD}{A\epsilon_{o}}

Now, from the above eqn  we can say that:

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Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.

4 0
3 years ago
uphill at a rate of 2.5 mi/h from the base of a 6-mi trail. At the same time, Edwin walks downhill at a rate of 3.5 mi/h from th
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Speed of downhill person = 3.5 miles per hour

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electricity flows back and forth in an lc circuit with a .33 f capacitor and a .1 h inductor. what is the angular frequency and
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I have an object that I want to know when it was made. I calculate that the object contains 0.12g of Iodine-131 but started with
Sav [38]

Answer: 71.72 days

Explanation:

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A=A_{o}.2^{\frac{-t}{h}} (1)  

Where:  

A=0.12 g is the final amount of Iodine-131

A_{o}=60 g is the initial amount of Iodine-131

t is the time elapsed  

h=8 days is the half life of Iodine-131

Knowing this, let's substitute the values and find t from (1):

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Applying natural logarithm in both sides:

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Finding t:

t=71.72 days

7 0
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